Adv Illustration – A Ball Sliding inside a Cylindrical Groove-2 | System of Particles #5 for JEE Adv

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Questions asked in JEE Advanced are based on critical thought processes rather than direct application of concepts. For preparation of JEE Advanced, students have to focus on problems based on multi concept applications.

Ashish Arora Sir has taken up a case of A Ball Sliding inside a Cylindrical Groove-2 from the chapter System of Particles which is important for select in IIT. System of Particles covered in Class 11 NCERT and is crucial in JEE preparation. These advanced illustrations cover all formulas and relevant solved examples from system of particles and are useful for making notes for IIT JEE preparation.

System of particles is one of the most critical sections of Mechanics in which questions are asked in JEE. This set of advanced illustrations covers questions on collision, compression in spring, center of mass, rocket ejection, elastic collision, coefficient of restitution, pendulum, potential energy, kinetic energy in collision cases, angle of divergence, bullet, displacement of center of mass, momentum, trolley cases, chain falling on a table. Questions have been asked on these concepts in previous years in JEE Mains, JEE Advanced and Olympiads.

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This problem can also be done like this:-
1/2 (mew) V^2 = mgr(1-cos theta)

Marktwaina
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1/2 mew v rel square= mgr(1-cos theta)
Here v rel at bottom= √(2gr)
At right extreme=0

tsamrawat
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2:34
Sir I think the system's energy cannot be conserved from top point to the required point because of the external force by the wall. But for the ball it can be conserved from top to the bottom most point and then for the system from this point to the required point. So although we are getting the same result by conserving energy of the system for the entire time, maybe it's wrong to think this way and the result may not be more than just a coincidence. Please sir let me know if I'm correct.

gourav
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Wow sir i was trying WET between intermediate and final point..though got same result but WET b/w final and initial is too easy for calculation..thanks sir..

nitish
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Wrt block means final velocity is zero

vishalchandel
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respected sir shouldn't the work done by gravity be mgr(1-cos(theta))

dhruvaggarwal
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Can't we conserve energy from the bottom instead of starting point ..

satvik_srivastav
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How the printed questions comes on paper on which you are writing??

themysterious
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Why is it MgRcos(theta) and not MgR[1-cos(theta)] ??

Ashutosh._.Gupta_
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But sir why didn't you consider the effect of normal reaction on groove in the previous ( problem #4)??? Plzz answer.

MazharKhan-dlfc
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Sir why momentum is not conserved from starting position of ball but from bottom most you are conserving it. Please reply.

divitgoyal
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sir why work done by gravity is mgrcostheta .And when ball and block move together with same velocity, why don't we consider the work done by gravity then. please help

srisravyavukyam
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is qquestion me gravity ka work done r(1-cos(x))hoga na sir pls reply kijiyaga

amiteshmanitiwari
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Sir can we solve this question using centre of mass in y direction

oooo
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When it goes other half groove the velocity is toward left then why assume right

jaykishan
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physics Galaxy sir you have tought us earlier in circular motion to get angle we use cos (theta)= (2gr)-u2/2gr in this problem can we find angle like dis method??

sushantbhardwaj
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Sir when wedge is moving then in hoizontal dirn. There is normal force .. So how can momentum. Be conserved ?

adarshchaturvedi
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why cant we apply conservation of mechanical energy??? as the work done by external forces is zero and there is no non conservative force than why cant we apply conservation of mechanical energy?

vanshmishra
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sir, can the concept of reduced mass be applied to solve the above problem

amitanshupattanayak
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Sir I am a dropper ..i have solved this problem in com frame ...and got the same result ...(can it be used for shotcuts as i got the result in just one line )

humanhuman