Graphing Linear Equation “2𝑥 + 𝑦 = 6” Using Intercepts | Step-by-Step Algebra - Math Doodle

preview_player
Показать описание
This video will guide you through [How to Graph Equation “2𝑥 + 𝑦 = 6” Using Intercepts].

📌 How to Graph a Linear Equation Using Intercepts
✓ Step 1. Find the 𝑥- and 𝑦-intercepts of the line.
- To find the 𝑥-intercept: Let 𝑦 = 0 and solve for 𝑥
- To find the 𝑦-intercept: Let 𝑥 = 0 and solve for 𝑦
✓ Step 2. Find a third solution to the equation.
✓ Step 3. Plot the three points and check that they line up.
✓ Step 4. Draw the line.

🔑 Key Things to Remember:
☞ 𝑥-intercept ➜ the point where the line crosses the 𝑥-axis. It has the form (𝑎, 0).
☞ 𝑦-intercept ➜ the point where the line crosses the 𝑦-axis. It has the form (0, 𝑏).

〰️
✅ More BITE-SIZE VIDEOS on "Graphing Linear Equations”

〰️

〰️

〰️
📖 About Math Doodle: This channel is our effort to support students, teachers, and parents by sharing our tutorial and problem-walkthrough contents that cover a wide range of algebra topics!

Hopefully, you have found the math help you were looking for! 🙏 Thank you for checking out our videos! 💯

〰️
🌏 Translated titles and subtitles have been added to this video:
Spanish: Graficar “2x + y = 6” usando intersecciones
French: Représentation graphique de "2x + y = 6" à l'aide d'intersections
German: Grafische Darstellung von „2x + y = 6“ unter Verwendung von Abschnitten
Portuguese: Representação gráfica de “2x + y = 6” usando interceptações
Hindi: इंटरसेप्ट का उपयोग करके "2x + y = 6" रेखांकन करना
Filipino: Pag-graph ng "2x + y = 6" gamit ang Intercepts
Indonesian: Grafik “2x + y = 6” menggunakan Intercepts
Japanese: 切片を使用して「2x + y = 6」をグラフ化する
Russian: График «2x + y = 6» с использованием Intercepts
Vietnamese: Vẽ đồ thị “2x + y = 6” bằng cách sử dụng Intercept
Рекомендации по теме
Комментарии
Автор

Great video as well as explanation sir 👍

pro-qnyf
Автор

Interesting. I was never taught to substitute zero for the variables. Instead, we were taught to arbitrarily plug a value into x and solve for y, then plug a different value into x and solve for y again, then graph the line and find the x- and y-intercepts.

I suppose using zero for either would have been much faster.

THall-vicp