Impossible Equation to Solve | MindSphere

solve the equation for x, how to solve hard maths question, math Olympiad, hard maths problem in usa, Oxford maths, maths bee, international maths#maths
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[Maths_.]

This is my honest review. The only tricky part is the inverse concept, but it's still not something that requires out-of-the-box thinking. Everything before and after that flows naturally with practice. To be honest, someone with a bit of familiarity with Olympiad-style algebra should be able to solve this, as the tricks found there are truly mind-blowing.

[coke-cane]

That was so
Thanks for teaching me your tricks master

[guillermobarrio]

I would have thought the answer was to be pretty close to 2022... boy, was I wrong. Thanks for the vid!!

[朕是神]

How to solve (derp version):
1. Take the natural log of both sides.
2. Notice that there's no simple way the x makes the ln(1+1/x) be a fraction of ln(1+1/2022).
3. Notice that this is a youtube video popular enough to be recommended to you, and as such the solution must be simple.
4. So the only other way is 1+x=+-2022.
5. Check the two candidates.
6. Facepalm as you realize that you managed to avoid doing math while solving a math problem for fun.

[devooko]

wow that "Adding 1 and subtracting 1" step is pure genius. First time seeing something like this. Thank you !

[ashishjat]

At the first look, i think yhere is no. Solution of given problems.
But i am shocked by the steps you followed and also by the integer solution 🎉🎉❤
Nice problem .
I have learned many more from this ❤🎉
Thank you ❤

[BbIQ]

Brother, please, can you create a course to learn the manim library for beginners?

[gouravsaini]

Please Upload more questions and more theorems daily❤. SOON YOU BECOME FAMOUS❤❤❤❤😊😊😊

[jlpadilha]

I got the same setting y=x+1. Then so y=-2022 and by x=y-1 you get x=-2023.

[yurenchu]

(1 + 1/x)^(x+1) = (1 + 1/2022)^2022
... substitute n = -x ...
(1 - 1/n)^(-n+1) = (1 + 1/2022)^2022
((n - 1)/n)^(-n+1) = (1 + 1/2022)^2022
(n/(n - 1))^(n-1) = (1 + 1/2022)^2022
((n-1+1)/(n - 1))^(n-1) = (1 + 1/2022)^2022
(1 + 1/(n-1))^(n-1) = (1 + 1/2022)^2022
(n-1) = 2022
n = 2023
x = -n = -2023

[Lws-]

Mind blowing!! In first look I thought that the question is wrong lol

[serhiislobodianiuk]

Do you understand that you haven't solved the problem? You found one solution and have no proof that there are no other solutions.