In the figure two curved plastic rods, one of charge +q and the other of charge -q

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In the figure two curved plastic rods, one of charge +q and the other of charge -q, form a circle of radius R = 8.50 cm in an xy plane. The x axis passes through both of the connecting points, and the charge is distributed uniformly on both rods. If q = 15.0 pC, what are the (a) magnitude and (b) direction (relative to the positive direction of the x axis) of the electric field E produced at P, the center of the circle?
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louiemanzella
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KavinKumarNR
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moaiya
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you are so amazing im honestly learning everything my professor cant explain.

MrSuperRatchet
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Why are you multiplying by SinTheta at 2:55 and not CosTheta? Can't you rearrange the vectors to that the orientation of the right triangle made by the vectors is such that it would make sense to multiply by CosTheta? How do you know whether to use Cos or Sin?

AndrewCheetah
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I struggled hard with this problem, thanks for helping me understand it

rrrwarrior
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A circular plastic disk with radius R 2.00 cm has a uniformly
distributed charge Q(2.00x10^6)e on one face. A circular
ring of width 30 mm is centered on that face, with the center
of that width at radius r 0.50 cm. In coulombs, what charge is
contained within the width of the ring?

Nicolebedine
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hi sir, if you mentioned that the x-components have been cancelled out, assume that dE1-dE2 = 0, why shouldn't the y-components be dE1+dE2 = 2 sin delta? instead sir's explanation was sin delta only

StudyAccountshanyue
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So if the net electric field is basically four times the magnitude of the y-component of the electric field, why did you draw 5 arrows at 6:49? Or is that just more of an "illustration" to show that there are "several" forces of the electric field in that direction?

mattooi
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Very clear explanations. I subscribed.

arashalphonso
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Ahmadkh-qpgv
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Thank you so much, you are very very helpful

Nicolebedine
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can someone please explain to me why s is equal to r theta?

hankmoody
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rahiq, stop looking at these i can see you through your laptop.... you are not

Tristan-kx