Binomial Theorem 04 l Last two digits l Divisibility & Remainder problem l JEE/BITSAT/CET/Class 11

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In the video, applications of binomial expansion such as finding last two digits, divisibility and remainder are discussed alongwith examples from JEE Mains and JEE Advanced.

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Class 11 Chapter 8 : Binomial Theorem 01 l Binomial Expansion l General Term l Middle term lJEE/BITSAT/CET/Class 11

Class 11 Chapter 8 : Binomial Theorem 02 l Problems on General Term l Middle term l JEE/BITSAT/CET/ Class 11

Class 11 Chapter 8 : Binomial Theorem 03 l Multinomial Expansion l JEE/BITSAT/MHTCET/CBSE/HSC/Class 11

Class 11 Chapter 8 : Binomial Theorem 04 l Last two digits l Divisibility & Remainder problem l JEE/BITSAT/CET/Class 11

Class 11 Chapter 8 : Binomial Theorem 05 l Greatest Term l Integer & fraction problems l JEE/BITSAT/CET/CBSE/Class 11

Class 11 Chapter 8 : Binomial Theorem 06 l Analysis of Binomial Coefficients Part 1 l JEE/BITSAT/CET/CBSE/Class 11

Class 11 Chapter 8 : Binomial Theorem 07 l Analysis of Binomial Coefficients Part 2 l JEE/BITSAT/CET/CBSE/Class 11

Class 11 Chapter 8 : Binomial Theorem 08 l Multiplication of series l JEE Mains/JEE Advanced/BITSAT/CET/Class 11

Class 11 Chapter 8 : Binomial Theorem 09 l Binomial expansion for any index l JEE/BITSAT/CET/CBSE/Class 11

Class 11 Chapter 8 : Binomial Theorem 10 l Double Summation l JEE Advanced/JEE Mains/BITSAT/CET/CBSE/Class 11
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Aree waah 😭😭😭❤️❤️❤️👍👍💯💯 majaa aa gaya sir, kya mast padhaye hain aap.

Parth_Jaiswal_IIT_BHU
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Wow sir aap kitna bdiya samjhate ho I am facing problems in this portion bcoz in my coaching this topic is completed in only 15min but after watching this all of my concepts and doubts are cleared
Thank you sir keep going on one day your youtube channel will reach 100M subscribers

uditsaini
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Very well explained sir u have cleared all my doubt . thanks a lot sir

studentofcollege
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Thank you sir for clearing my doubts🔥🔥🔥🔥

anandhiparasu
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Randomly find yr channel and yr teaching style is amazing. You didn't left any of the concept. Most satisfying video❤️

mittalchoudhary
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Very much thanks, this was great explanation.

Parth_Jaiswal_IIT_BHU
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Thank u sir u teach very well, hope your subscribers will increase fastly

sameermishra
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God level explanation
Thank u so much!!

rohan-
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Great explanation! But I think the last question could easily be done by changing 32^32 to 2^160 then 2^3= 1+7

sibohampattanayak
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After searching a lot finally got this video.
Very nice explanation.

sushilpatankar
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Very helpful 1 day before my jee exam 😍

amansawarnaya
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I think God is with me.i got this video suddenly and i realised that how important is this for my preparation.
Thank you very much sir.💗❤❤❤❤❤❤❤❤❤💗💗❤❤💗💗💗💗💗💗💗💗

dut_uut
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Sir agar 2nd question me -ve sign se multiple kiya to nhi chalega kya??
Dono se answer alag alag aa rhe hai..

moreanushka
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Sir ap kafi acha parhate hai thank you

urpaps
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sir for the last question, it is a 3 liner, such an extensive calculation is not required

shreyankpal
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Which book you use of maths for jee ??

Please reply sir

riteshbagde
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Sir u teach so well but not have subscribes as much as you deserve

berojgarvlogs
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sir lastr question me remainder 4^32 hoga 4^342/7

mobile_o_graphy
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Sir 2 nd question of last term was wrong multiplication

kesariyt
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sir 1st example me 100p ka sign change kyu ni hua ye smjh ni ayaa

harshitmishra