Calculus 3: Partial Derivative (27 of 50) The Chain Rule (Type 2)

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In this video I will explain and demonstrate another method (2) of using the chain rule to find dy/dx=? of x^3+y^3-10=0.

Next video in the series can be seen at:
  1. Michel van Biezen
  2. ilectureonline
  3. ilectureonline.com
  4. Mike
  5. Mike van Biezen
  6. van Biezen
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Комментарии
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Thank you very much for all the lectures you (and everyone else involved) have put online.

I found your reference to the product rule on y^2*x (when taking the derivative with respect to x) confusing at first. Then I went through my notes and remembered it was 'implicit differentiation.'

So just in case anyone else runs into the same problem, that's the ticket.

countzero
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thank you professor you are the light in the end of my University tunnel

theson
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Thank you! I didn't know if/when this would be covered in my course and couldn't quite understand how we could do
[d/dx(lny=e^x)] = [(1/y)(dy/dx)=e^x]
but couldn't do the same for multivariable functions.
∂ vs d, man.

ggieseBC
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thank you the video is a relief for me

saidmohamed
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Thank you so much sir its quite informative for me .

AfzalKhan-rwbh
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why is it negative? where does the minus sign came from

jaspersarmiento
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Why there is dy/dx after x.2y at the time of video 2.18. Is'n the derivative of y^2.x = y^2.1 + x.2y . Why we put dy/dx after that ?

fatihinal