MM41: Complex Fourier series

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Yes, extremely well explained. Well done.

philcooper
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Thank you from the bottom of my heart. You are really a great teacher. Thank you

حنينبيبي-ثط
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Thank you so much. I was confused as to how the constant came to be singular and one only 😅(I was comparing it to the standard condition)

shidzboutogodown
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Sir, for e^-i*n*theta= cos(n*theta)+isin(n*theta),
It should be
e^-i*n*theta = cos(n*theta) - i sin(n*theta)
right?

hongheng
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alot of mistakes man e^-inpi = cos(-npi) + isin(-npi) = cos(npi) + 0 = (-1)^n

pro_coder
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Can you please explain me how you got the negative sign in e^(-i*n*pi*x)/l?

tron
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hello sir thanks for the explanation. i am doing a question where p=4 and therefore r=2. is e^(-n pi i/2)=(i)^n?

ritesha
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Boss the limits of the integral have to be 0 and 2 right; you've written 0, 1. Otherwise great video!😄Thank you

the_boi_man