Hydrostatic Force Problems - Calculus 2

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This calculus 2 video tutorial explains how to find the hydrostatic force on a plane surface submerged in water. This video contains plenty of examples and practice problems of finding the fluid force acting on a vertical submerged plate. Examples include the square, right triangle, isosceles trapezoid, and the semicircle. The weight density of water is 9800 N/m^3 or 62.4 lbs/ft^3.

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Professor Organic Chemistry Tutor, thank you for a solid explanation of Hydrostatic Force problems in Calculus Two. Drawing a picture is a great way to solved Hydrostatic Force Problems in Calculus. There is an error in this video at about the 7:26 minute mark therefore, I will rewatch this video from start to finish.

georgesadler
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why is this in calc 2. this is gonna take me at least 6 hours to master.

saberspeed
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Thank you so much
I understood it
Lots of love from Nepal

RameshKumar-lirp
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I know why the slope is -2/3 and not -3/2. The equation of the slope in terms of x is y=-3/2x - 3. However, you want to rearrange the equation so that x is by itself. Therefore, using algebra,
y=-3/2x - 3
y+3 = -3/2x
-2/3y - 2 = x
Writing this as L(y)
L(y) = -2/3y - 2

PowerOfTheBanana
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F = yhA

y = unit weight (9.8kN/m³ or 62.4lbs/ft³)
h = distance from water surface to centroid of the shape
A = area of the shape

Smile-etfe
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Seems to be confusion in the comments section, slope is not "rise over run." In this case, it is better to think of slope as change in (function) over change in (variable), just like how rise over run is delta f(x) over delta x.

Hope this helps!

winsurely
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I love you, sir. When I have money one day, I will be sure to support you.

graceful
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Thank you so much Sir for this Video it really saves me in understanding the concept, rather than just reading it in the textbook . more power.

vinceojeda
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For the example with the trapezoid, wouldn't your slope calculation be wrong because you don't actually know the length of the top half on your grid, you only know it's 12 ft + some amount on the x axis?

dylanarmstrong
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Thank you thank you thank you this made no sense until I watched this vid

kensielwell
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At 8:33, the function for length of the strip should be: L(y) = -(2/3) * (y+3) ; because y = -(3/2)x - 3

Hope this helps someone out

Exoulos
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Thank you so much, bringing these videos for my final in a few hours.

Kyle-pjvc
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Great explanation but for me it would be better to locate the origin at the base of the figure so that the limits will be more easier to calculate (if you don't want to use calcu)

jp
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Shouldn't the slope be -3/2 at 7:26? 6 and 0 are x-values and should be in the denominator since the slope formula is (y2-y1)/(x2-x1)

makenzie
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Confused on how you got slope. Looks like this is change in x divided by change in y instead of change in y divided by change in x.

mdavis
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Isn't the slope at 7:40 -3/2? since it's y2-y1 / x2 - x1 ?

User-cisu
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I don't understand the second example. As far as I rememberit's rise over run so isn't it supposed to be -3/2?

kyanisekaildelmonte
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Thank you so much. Always come back to the same place for the help i need

hocnguyen
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Can you do a video like a qna for us to get to know you better I like attachments to people that teach me????!!!

HeadlessHoursemanMC
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youtube > Univercity bro you saved me so many times

georgebartman