Second Largest Number From List | Coding Questions in Python | Python Interview Questions

Second Largest Number From List | Coding Questions in Python | Python Interview Questions
This video is part of python coding questions and answers. In this video,i have explained one more Coding Question with proper explanation.

1) Infosys Coding Question
2) Logical Questions in Python
3) Infosys Interview Questions and Answers

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[python]

Humesha ke trha ya vedio bhi bht Help full rha thank you sir ❤❤❤bht acha explain kiy apne

[Cloudxxx]

3:01 Hi. You didn't explain why it needs to add [0] next to nums.

[propagandabuster]

Best code for this problem is given below,

y=[ 2, 3, 6, 6, 5 ]
y.sort(reverse=True)
for i in y:
if (i<max(y)):
print(i)
break

[niravparekh]

def find_max_min_number(array):


 

    largest_num=array[0]

    second_largest_num=0


 

    for i in array:

        if i > largest_num:

            largest_num=i


 

    print("Largest number is:", largest_num)


 

    for i in array:

        if i > second_largest_num and i !=largest_num:

            second_largest_num=i

    print("Second Largest Number:=", second_largest_num)

   

array_range=int(input("Enter Array Range:"))

loop_counter=0


 

nums=[]

for i in range(array_range):

    loop_counter+=1

    print(loop_counter, end=" ")

    element=int(input("Enter Array Element:"))

    nums.append(element)


 

array=[]

for i in nums:

    if i not in array:

        array.append(i)


 

print('Remove All Dublicates:', array)

find_max_min_number(array)

[afreedpasha]

nums = [159, 78, 91, 29, 159, 99]
f_lar = nums[0]
s_lar = nums[1]
for i in range(len(nums)):
if nums[i]>f_lar:
f_lar=nums[i]
for i in range(len(nums)):
if nums[i]>s_lar and nums[i]!=f_lar:
s_lar=nums[i]
print(s_lar)

[Mahesh_]

What if we want third largest in manual way ?

[aparnachouhan]

its not largest number is in 0 index so largest and second largest output will be same

[afreedpasha]

second_largest = nums[1] then we are getting right answer if we take second_largest as nums[0] we will get the first_largest value only

[shanvikgowda]

in simple way
first_largest=max(nums)
second_largest=nums[0]
for i in range(len(nums)):
if nums[i]>second_largest and nums[i]!=first_largest:
second_largest=nums[i]
print(second_largest)

[ramunagaram]

This code will not work for second Highest value if 0 element of the the list is the highest number Ex: lst1= [100, 45, 76, 9, 23, 37, 84, 1]