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Numerical Methods in Python Series - Fixed Iteration Point Method

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Numerical Methods in Python Series - Fixed Iteration Point Method
this tutorial will show you how to solve non linear equation in Python using Fixed Iteration Point
steps:
1. watch previous video:
Numerical Methods in Python Series - Calculating Taylor Series for Exponential Function
Numerical Methods in Python Series - Solving Non Linear Equations
Numerical Methods in Python Series - Bisection Method
Numerical Methods in Python Series - Regula Falsi Method
Numerical Methods in Python Series - Newton-Raphson Method
2. the method

3. the function is:
f(x) = e^x - 5x^2
with initial guess
x = 1
and
epsilon = 0.00001
the result shows that the solution is convergence to 0.605270
4. try for
f(x) = x^3 - 2x^2 -5
with initial guess
x = 4
with
epsilon = 0.00001
the result shows that the solution is convergence to 2.690656
5. try for
f(x) = x^3 - x - 2
with initial guess
x = 2
with
epsilon = 0.00001
the result shows that the solution is convergence to 1.521380
we will learn more about solving non linear equations with Secant method in the next tutorial ;)
and at the end we will compare the results of each methods ;)
you can get the code from GitHub:
References:
thanks for watching, don’t forget to subscribe, activate the notification bell, like this video and also share it to support this channel to be able to continuously creates useful tutorials :)
leave us some comments if there is any questions and let us know what you think :)
Intro and Outro created by ProCodeCG Kids: Islamey Fawwaz Alfattan
this tutorial will show you how to solve non linear equation in Python using Fixed Iteration Point
steps:
1. watch previous video:
Numerical Methods in Python Series - Calculating Taylor Series for Exponential Function
Numerical Methods in Python Series - Solving Non Linear Equations
Numerical Methods in Python Series - Bisection Method
Numerical Methods in Python Series - Regula Falsi Method
Numerical Methods in Python Series - Newton-Raphson Method
2. the method

3. the function is:
f(x) = e^x - 5x^2
with initial guess
x = 1
and
epsilon = 0.00001
the result shows that the solution is convergence to 0.605270
4. try for
f(x) = x^3 - 2x^2 -5
with initial guess
x = 4
with
epsilon = 0.00001
the result shows that the solution is convergence to 2.690656
5. try for
f(x) = x^3 - x - 2
with initial guess
x = 2
with
epsilon = 0.00001
the result shows that the solution is convergence to 1.521380
we will learn more about solving non linear equations with Secant method in the next tutorial ;)
and at the end we will compare the results of each methods ;)
you can get the code from GitHub:
References:
thanks for watching, don’t forget to subscribe, activate the notification bell, like this video and also share it to support this channel to be able to continuously creates useful tutorials :)
leave us some comments if there is any questions and let us know what you think :)
Intro and Outro created by ProCodeCG Kids: Islamey Fawwaz Alfattan