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Numerical Methods in Python Series - Secant Method
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Numerical Methods in Python Series - Secant Method
this tutorial will show you how to solve non linear equation in Python using Secant Method
steps:
1. watch previous video:
Numerical Methods in Python Series - Calculating Taylor Series for Exponential Function
Numerical Methods in Python Series - Solving Non Linear Equations
Numerical Methods in Python Series - Bisection Method
Numerical Methods in Python Series - Regula Falsi Method
Numerical Methods in Python Series - Newton-Raphson Method
Numerical Methods in Python Series - Fixed Iteration Point Method
2. the method

3. the function is:
f(x) = e^x - 5x^2
with
x = 4
x_before = 0
x0 = 2
x1 = 4
and
epsilon = 0.00001
the result shows that the solution is convergence to 0.605267
4. try for
f(x) = x^3 - 2x^2 -5
with
x =4
x_before = 0
x0 = 2
x1 = 3
with
epsilon = 0.00001
the result shows that the solution is convergence to 2.690647
5. try for
f(x) = x^3 - x - 2
with
x = 4
x_before = 0
x0 = 1
x1 = 2
with
epsilon = 0.00001
the result shows that the solution is convergence to 1.521380
we will compare the results of each methods in the next tutorial ;)
you can get the code from GitHub:
References:
thanks for watching, don’t forget to subscribe, activate the notification bell, like this video and also share it to support this channel to be able to continuously creates useful tutorials :)
leave us some comments if there is any questions and let us know what you think :)
Intro and Outro created by ProCodeCG Kids: Islamey Fawwaz Alfattan
this tutorial will show you how to solve non linear equation in Python using Secant Method
steps:
1. watch previous video:
Numerical Methods in Python Series - Calculating Taylor Series for Exponential Function
Numerical Methods in Python Series - Solving Non Linear Equations
Numerical Methods in Python Series - Bisection Method
Numerical Methods in Python Series - Regula Falsi Method
Numerical Methods in Python Series - Newton-Raphson Method
Numerical Methods in Python Series - Fixed Iteration Point Method
2. the method

3. the function is:
f(x) = e^x - 5x^2
with
x = 4
x_before = 0
x0 = 2
x1 = 4
and
epsilon = 0.00001
the result shows that the solution is convergence to 0.605267
4. try for
f(x) = x^3 - 2x^2 -5
with
x =4
x_before = 0
x0 = 2
x1 = 3
with
epsilon = 0.00001
the result shows that the solution is convergence to 2.690647
5. try for
f(x) = x^3 - x - 2
with
x = 4
x_before = 0
x0 = 1
x1 = 2
with
epsilon = 0.00001
the result shows that the solution is convergence to 1.521380
we will compare the results of each methods in the next tutorial ;)
you can get the code from GitHub:
References:
thanks for watching, don’t forget to subscribe, activate the notification bell, like this video and also share it to support this channel to be able to continuously creates useful tutorials :)
leave us some comments if there is any questions and let us know what you think :)
Intro and Outro created by ProCodeCG Kids: Islamey Fawwaz Alfattan