A-Level Maths B9-26 Graph Transformations: Using BIDMAS

[AceOfHearts]

Content which textbooks won't cover.... awesome stuff

Someone give this man an award!

[RamBahadur-loor]

Astounding how there isn't a single video besided this which properly clarifes the order of transformations. Thanks Jack.

[stefaniadalberto]

YOU ARE A LIFE SAVIOUR SIR!!! THANK YOU SO MUCH, MAY GOD BLESS YOU💫💫💫💫

[jaffacake]

This is super helpful I wish I could super like the video!

[leaf-slqp]

Would we ever have to do reflections within composite transformations? and if so where would they go in the order? Thanks

[van]

Can I please enquire - how do I (if this is possible) utilise the "BIDMAS v anti-BIDMAS" rule for this problem?

Given f(x) = ln(x), sketch | f(-x) | and determine where the transformed curve crosses the x-axis.

So, quick sanity check please: Two transformations: a modulus operation and a reflection (in the y-axis). Agree?

If both operations are deemed to be acting parallel to the same axis then the order they are applied is relevant. Conversely, the order they are applied is not relevant.

Assumption 1: A Reflection in the y-axis is a stretch with scale factor -1 parallel to the x axis.

Therefore, if Assumption 1 is correct, then if the Modulus operation is deemed a transformation parallel to the x-axis then the order the transforms are applied is relevant. Do you agree that the Modulus operation is a transformation parallel to the x-axis?

<Aside> Assuming I have performed the transformations correctly (big assumption) I do indeed get different results when applying the transformations in different order i.e. Case 1: Modulus followed by Reflection. Case 2: Reflection followed by Modulus. </Aside>

Therefore, it appears that order IS RELEVANT and hence the Modulus transformation is a transformation parallel to x-axis. Agreed?

Assumption 2: It appears that, comparing Case 1 and Case 2 against the result obtained on a CG-50 then performing the Reflection followed by the Modulus transformation provides the required solution.

So if both transformations are parallel to the x-axis then anti-BIDMAS applies? The Stretch (SF = -1) being represented by the "M" in BIDMAS, what would the Modulus be represented by?

Hope this all makes sense. Thanks for your consideration.

[H-ho]

Why do teachers not teach this, makes it so much easier

[giovannipaoloboyd-trevisan]

Thank you! I wish i came across this earlier

[syro]

These videos have been really helpful. Could you make a video where there are two vertical transformations and two horizontal transformations?
Like how x^3 is transformed to -0.5((2x+1)^3)-2