Rational inequalities 2 | Polynomial and rational functions | Algebra II | Khan Academy

Slightly harder rational inequality problem

Missed the previous lesson?

Algebra II on Khan Academy: Your studies in algebra 1 have built a solid foundation from which you can explore linear equations, inequalities, and functions. In algebra 2 we build upon that foundation and not only extend our knowledge of algebra 1, but slowly become capable of tackling the BIG questions of the universe. We'll again touch on systems of equations, inequalities, and functions...but we'll also address exponential and logarithmic functions, logarithms, imaginary and complex numbers, conic sections, and matrices. Don't let these big words intimidate you. We're on this journey with you!

About Khan Academy: Khan Academy offers practice exercises, instructional videos, and a personalized learning dashboard that empower learners to study at their own pace in and outside of the classroom. We tackle math, science, computer programming, history, art history, economics, and more. Our math missions guide learners from kindergarten to calculus using state-of-the-art, adaptive technology that identifies strengths and learning gaps. We've also partnered with institutions like NASA, The Museum of Modern Art, The California Academy of Sciences, and MIT to offer specialized content.

For free. For everyone. Forever. #YouCanLearnAnything

Subscribe to Khan Academy’s Algebra II channel:

[Marshmallow-ckoo]

Gosh I hate math at the times I don’t understand it, I feel so stupid by the way it’s presented to a large number of us in the classroom. Sometimes others require certain teaching methods. But whatever. I wish I could freely ask questions about this but it’s just too intimidating. But this video sure helped.

[fundamentalsofphysicsnmath]

Thanks for such a nice explanation. Love you from

[xboxiscool]

Thank you for helping me with my math, keep up the good work...

[sarazebari]

finally, I get it thank you so much really

[ilinaeternity]

This helped a ton.. I think I finally get it.. Thanks :)!

[alihamed]

in min 2:17 if you would have left the x on the left side it would have been -x>/11 and then we divide by -1 both side it would have been x\<-11 or am i wrong?

[piroton]

this is excellent work. Thank you so much for helping us poor students understand this confounding topic XD

[tholaalw]

It would be much easier if you used sign table. 

[KillerBearsaw]

Not gonna lie, 7:30 blew my mind, dunno how i missed that all this time.

[nandaprian]

does rational inequalities involving modulus be solved the same way?

[rachimbaskin]

Clear throughout this toughie. A fellow teacher thanks you.

[kyl]

what is the answer if you used sign table?

[frankieffbaby]

I​ need to see this with a single whole number in the denominator. like 5k-5 / 5 > 4

[tsurek]

This video is all over the place. How about best practice way to solve the problem, using a sign graph and giving us the answer. I dont even know how to solve this problem after spending 11mins watching this....

[Ommbye]

Explaination is clear doing BSc Econ. but not so good in math we 'll watch more video

[AnuragPradhan]

/how to solve this type of question <x>-1/<x>-2>0, here<> means modulus.

[sparks]

I don't understand why x is smaller or = to -11, and x is bigger then -4 cannot work. Can't it be true on a graph. Wait, can this only be correct if there is an x squared in the rational inequality?

[natashastokes]

Can someone please explain when you have something like 3 < (x in the denominator) < 4

[dpw]

It's an extraneous solution. 2:40

[sagialagem]

you are my greek god! thanks... so helpful!