Reflect on this binary laser puzzle.... #computerscience #physics #counting

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Back at it... part 2 of the lasers puzzles of puzzles! This time with some fun reflecting components! Can you figure it out? Subscribe for part 3, which might feature some logic gates :)
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It'll be 11 if we don't loose any rays

upd: yeah, we actuality don't loose rays here -- dashes on mirrors make sense.

klioda
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The max number is 15, how ppl got more than that is beyond me. :D Anyway it stays the same, 13.

Dave-McRae
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this laser emitter emits the binary based number, and the receiver is reversed, wich means the emitter goes right to left while the receiver receives left to right.

in the mirrors level, the mirros just swap 2 lasers places, so while the emitter is emitting 1101, the receiver is receiving that same number, but since it's reversed, it's receiving 1011, wich is binary for decimal 11 and that's the number that should show up in the display

braziliangentleman
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1st goes to 1st place
2nd goes to 4th place
3rd goes to 3rd place
4th goes to 2nd places
So the mirrors just swap the 2nd and 4th output.

The two boxes are the same box, and both boxes are just binary from right to left ascending

The output from the bottom box is 1101 (=13)

Without the mirrors, the top box would've received 1011 (=11), but with the mirrors the 2nd and 4th inputs swap, so the box receives 1110 (=14) instead.

So the answer is 14

JakubS
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11??

Edit: and actually looking at it if im right, with or without mirrors, the top box would give the same output of 11

vyiqqce
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I thought the mirrors were optics ovals…

britkaminky
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39? Idk if there was a previous video explaining more to this but that’s what I got.

GenericOceanLinerHistorian
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