Central Limit Theorem - proof part 1

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How do you get a minus sign, in the e^x Taylor Series expansion? I don't get it because I thought it was e^x = 1 + x + x^2/2! etc....

huskmda
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Ben, I am finding that with a large group of sample r values, I get a mean of .46 but with  a population r value I get .9947
the r value is based on a 200 and 1000 moving average of a forex pair. my population size is about 300, 000.  I've been unable to figure out why my population r is near perfect, when clearly on the chart the two moving averages go opposite directions regularly. Ive used 3 different calucations for r, and they all agree. Is there some rule that makes a large population r calculation of this data type a skewed r value.  I also thought that CLT would keep the two r values closer to eachother. (mean of sample means of r, and the population r value) any insight would be greatly appreciated. I've been trying to solve it for weeks. thanks
John

johnkrone
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Why does the rest stay o(t²) after integrating?

seriousbusiness
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Why it is -t^2y^2/2 rather than + t^2y^2/2?

张婧-hh
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who on earth uses y instead of x, though it makes no difference. I guess you do that to make it look difficult.

murtithinker