19. Advance Illustration | Rigid Body Dynamics | Friction and Normal Reaction on falling Rod

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The website, aimed at nurturing grasping power students, has classroom lectures on almost all the topics. It is an outcome of 23-year long toil of Physics expert who has made it a mission to simplify the complexities of Physics.

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19 advance illustration example replicated in JEE Advanced 2019
what a coincidence sir

gowtam.
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6:12 Sir yadi friction coefficient Diya ho to f is equal to mu and se bhi n ki value nikal sakte hain..

Sudarshan_.
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Sir, you are great!
you are a teacher of around a million

bios
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This question came in Jee advanced mains what a coincidence

paragdey
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this question was fabulous i wasn't able to solve it completely got confused making last nlm equation and f up their
and i have nothing to add on to this question as it is literally a damn good question just to imagine which forces are acting where is a feat in itself
but a small add on we can do is add a force for dt time rather than a tap which will give the rod an initial angular speed making problem more complex

abdullabohra-jm
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exactly same question was asked in jee adv 2019

ayush
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Sir what is the significance of normal accereration, a.n ???

vijayvyas
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at 2:32 the torque should be mglsin θ/2

vinitasharma
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If we have considered the rotation about iaor then what should we take as the direction of normal acceleration

prabhatkumarverma
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Sir bas friction horizontal mei lag raha hai toh rod right kiyu nahi ja rahi

rainyranjan
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Sir, while applying work energy theorem why don't we include rotational work done by friction? Sir, in this case point of application of force doesn't move but torque due to friction does some rotational work about center of mass.

SumaidSyed
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sir I guess there is a big blunder. the is also translating apart from rotating so work done by mg should cause change in both types of KE, not just rotation K.E. plus there is friction action. so basically what you did in video should be only for very small angles. right?

nidhishgautam
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in 2 equation left is cos and right is sin

jagdishprasadbairva
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Sir i have found one inconsistency which is bothering me and i am not able to resolve it. Kindly hep. At some angle theta N will become zero and rod will loose contact so at the same angle friction force should also become zero but it is not happening from the final two expressions of N and f is the missing link sir ? I will be highly obliged if you can kindly guide on this. Regards

rmishra
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How do u take the direction of normal acceleration

prabhatkumarverma
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Sir
Here COM have a linear velocity then it will not have translational kinetic energy
Reply

oooo
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At :6:03 sec. Friction will act in horizontal right direction but for lower end does not slip, acceleration(normal) sin theta will act in left horizontal direction but
why take it in right side ? Sir

prathamrana
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sir where is instantaneous axis of rotation...please upload

prabhatkumarverma
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Sir, are most of your problems from Irodov?

harshag.
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Sir what's the difference between this question and question in which the rod is hinged, alpha and omega are coming out to be same, so just friction would be replaced by horizontal normal reaction due to hinge?

KaranDoshicool