Trigonometric Fourier Series

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Signal and System: Trigonometric Fourier Series
Topics Discussed:
1. Trigonometric Fourier Series Expansion.
2. Formulas involved in the Trigonometric Fourier Series Expansion.
3. Fourier coefficients for even signals.
4. Fourier coefficients for odd signals.

Music:
Axol x Alex Skrindo - You [NCS Release]

#SignalAndSystemByNeso #Signal&System #FourierSeries #TrigonometricFourierSeries
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"Symmterical abpout t-axis" it means that the positive and negative area is equal in magnitude.

hafizuddinsyed
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Homework answer: x(t) is not symmetrical, so it's dc/average value cannot be nule; x(t) is purely even which implies bn = 0 (there is no sines as components).

MatheusSilva-dragon
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*x(t) is not symmetrical about t-axis ==>a0#0,
*x(t) is symmetrical about y-axis==>x(t) is Even signal ==> bn = 0,
*an#0

dembashow
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Thank you very much for this video, your explanations are better than my profs's

der__forschera
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This is the best you tube channel for system and signal, with great detail

animeshverma
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Finally youtube has recommended a good lecture series.

kavinmoorthi
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Sir u r doing great job u are the best teacher we students are blessed to have a teacher like u, thanks very much

prakhartiwari
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this really helps me with my online learning during covid19 quarantine. thank you

sarahhughman
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Sir, You have no idea how much this videos worth to thousands of students arround the world. Thank you!!!!

adithyarajapakshe
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For homework question,
*a0* will be some DC or average value since it is not symmetrical to the t-axis.
*an* will be some value since it is even signal.
*bn* will be zero since it has no sine term.

Fantasticsman
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Sir i don't understand how the signals are symmetric about time axis. Can you clarify my doubt.

gopikrishnamoodu
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Bn = 0 ;
An and A0 are not equal to zero;


because that is even signal (An != 0 ) and since there is no signal below the X-axis(time axis) so it is not symmetric about time axis.
so it is clear...

gauravnagamaheswarpattem
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Bn =0, otherwise ≠0. Bcoz it's symmetry to y axis and not to x axis. The waveform doesn't going down. It's only on the positive region.

pk_officl
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Isnt "symmetrical about the t axis" a little vague here...? I guess it just means if the area above and below the t axis is the same, a0 is 0?

쥬마펠키키
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Not symmetric about t-axis and so a0 ≠0, signal is symmetric about x(t) axis and this makes it Even, an≠0, bn=0

samuelyawtenkorang
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Tq tq tq so...much sir . Ur teaching is better than my faculty ... I can easily understood Ur class
And once again tq sir...this is really fantastic YouTube channel for ECE studies...🤗🤗👍👍

rajkumari
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please explain how the signal is symmetric about time axis, i am confused.

tehreemsheikh
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it is an even signal, average,a^o=0,a^n not equal to 0 and b^n equal to 0....correct me if i am wrong

prabhakardas
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Hello! At around 12:08, you say that the saw tooth function (Fn. (ii)) is symmetric about the 't' axis. Symmetry generally means reflective symmetry. However, the function doesn't have a reflective symmetry. But since the amplitude is the same on both sides of the axis, they yield an average value of 0. This is probably why a0=0. Please comment.

snehdeep
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Thank you sir for resuming the lectures..hope this subject will be finished before GATE 2018 :)

RitayanMitraggmu