Parallelogram has both pairs of opposite sides equal (Theorem and Proof)

Friends,

This is a Math video. This is our fifth webisode (WB-5) on "Series 8 -- Quadrilaterals".
In this video, we learn that both pairs of opposite sides of a parallelogram are equal.

Then we go ahead and prove this theorem.

This video is suited for class-9 (Class-IX) or grade-9 kids.

Cheers,
Friends at Rising Pearl

[dostotussigreatho]

Hi Nagaveni,

If we are given a //gm say ABCD and say we join diagonal BD, then yes we can prove that two triangles thus formed - ABD and CDB are congruent using SSS rule. This is how -

1. AB=CD. [opposite sides of //gm are equal]
2. AD=BC[same reason].
3. BD is common to both triangles

Hence proved by SSS congruence theorem.

Hope that helps!

Cheers,

[nagaveniraghavendran]

In the webisode where a diagonal bisects a parallelogram into two congruent triangles, you showed that it can be proved using ASA congruence rule.Can it also be proved using SSS congruence rule .i.e. all sides are equal rule?

[AmanKumar-kzlz]

Can u teach optional math. If yes; please make a video on function

[rakhichouhan]

thanks for teaching
my concept is clear

[subhankardutta]

Thanks this is so helpful for me . Thanks