If in two triangles ABC and PQR, AB/QR = BC/PR = CA/PQ then:(A) ∆PQR ~ ∆CAB (B) ∆PQR ~ ∆ABC(C)

If in two triangles ABC and PQR, AB/QR = BC/PR = CA/PQ then:
(A) ∆PQR ~ ∆CAB (B) ∆PQR ~ ∆ABC
(C) ∆CBA ~ ∆POR (D) ∆BCA ~ ∆POR

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