Can you answer this basic Algebra 1 question?

[mrhtutoring]

I will post the answer tomorrow. 😊
The correct answer is B) Nonpositive only

[ogxh]

Did he really just give people over the internet homework?

[f.r.y]

√(a)² = |a|
Definition of absolute value:
If a>0 or a=0, |a| = a
If a<0, |a| = -a
Hence the answer is B. Nonpositive only

[jimmy]

He's good, Wish I had him as a teacher when i was in school. Would have saved me from hating math back then.

[murphybed]

This is great. Very smart idea. Make people participate and learn. This is really how you will get people to learn because your teaching makes peoppe want to know the answer. Only working it out yourself will make you remember.

[DavidMauas]

Your channel has quickly become one of my favorites ! 🎉 Keep it up, please!

[oddlyspecificmath]

It's nice to be reminded when these assertions are first posed. Thanks.

[wernergamper]

B) non positive only, because the square root gives you non negative values by definition.

[bartholomew]

Answer B is “nonpositives” — this includes all negatives AND zero.
This is the correct answer.
Remember “-x” on the right would always become positive, if you plugged in any negative number, say “-5”, because -(-5) would always be a positive number. And the left side would always be a positive number with any negative x.

[nono-bqbe]

This heavily depends on your definition of square root. Many people in the comments section are saying non positive only because sqrt(x^2) = abs(x), however this does not hold true for all cases as it can be useful to define sqrt(x^2) as + or - x, in which case the answer would be all reals. Something like this is usually up to opinion and/or use case, but I am of the personal opinion (x^n)^1/n = abs(x) and root n of x^n = (e^2*pi*k*i/n) * x is a better delegation of definitions.

[bottlecapbrony]

It helps to think of sqrt(x^2) as being equal to abs(x). Then, it is easy to visualize without graphing software, that y=-x and y=abs(x) are equal for all negative values.

[ThatUnknownDude_]

I think its gotta be non postives only (but 0 also cuz it works)... cuz like if you take the root to RHS, making it "x² = (-x)²" and then plugging in a negetive number like (-2), we get "(-2)² = (-(-2))²" which simplifies to "4 = 2² = 4"

great question!

[ARS-fidp]

sqrt(x^2)=|x|
If you graph |x| and -x you see two graphes intercept at negative numbers including zero
Answer choice is B

[darthtardis]

Since sqrt(x^2) is equal to absval(x), you can simply solve by graphing and you get (-inf, 0]

[tenesiss]

B, the square root of a squared number is basically the absolute value of it, problem is rhst if you take x > 0 -x is the opposite of it but if x < 0 -x will be the positive of it

[trucid]

sqrt(x^2) isn't something we're used to seeing. If you rewrite it as absolute value of x, |x|, then the equation becomes:
|x| = -x

In fact, we can get rid of the absolute value sign by looking at two different cases:
1. When x is positive, the equation is x = -x, which has only one solution at x = 0.
2. When x is negative, the equation is x = x, which is true for all negative numbers.

So the solution is x <= 0.

[moeberry]

Lot of people in the comments are posting examples of some solutions that work for this equation, however the real way to solve this problem is to first note is that sqrt(x^2)
=|x|>or equal to 0, which means -x must also be greater than or equal to 0 as well for this equation to hold. Therefore-x>or equal to 0 means x<or equal to 0. In other words Nonpositive.

[jayasuryaassassin]

Netizens are stunned to see the negative zero.

[nizogos]

Left hand side is abs(x), the equation abs(x)=-x is valid for all negative nunbers, its the definition of the abs(x) for x<0

[radhamroun]

People should memorize this property: √(x²) = |x|
So |x| = - x if and only if x is a negative real number