An Ecuador Olympiad Challenge | Crack This Septic Equation

An Ecuador Olympiad Challenge | Crack This Septic Equation

In this captivating YouTube video, embark on a journey of intellectual exploration as we delve into the intriguing world of the Ecuador Olympiad Challenge. Join us as we take on the formidable Septic Equation—a puzzle that will test your mathematical prowess and critical thinking skills. Get ready to unlock secrets, unravel complexities, and embrace the thrill of cracking this enigmatic equation that has baffled minds. Will you be the one to conquer the challenge? Tune in for an exhilarating experience that combines mathematics, problem-solving, and the excitement of competition!

Topics covered:
Math Olympiad Question
Septic equation
How to solve Septic Equation?
Math Olympiad
Algebra
Math Tricks
Quadratic formula
Algebraic identities
Algebraic manipulations
Substitutions
Synthetic division method
Real Solutions
Complex solutions
Quadratic equations
Algebraic Challenging Equations
Quadratic equations
How to solve Septic equations using algebraic identities?
Math Olympiad Preparation

11 Key moments of this video:
0:00 Introduction
0:51 Factoring
2:06 Solving Cubic Equation
2:30 Algebraic identities
3:34 Quadratic equations
3:49 Quadratic formula
4:55 Complex solutions
5:17 Quartic equation
6:10 Complex numbers
7:10 Solutions of Septic equations
8:00 Verification

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#EcuadorianMathematics
#OlympiadPreparation
#EcuadorianPuzzle
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#algebra #math #matholympiad #ecuador #matholympiadpreparation

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We'd love to hear from you! Did you manage to solve the equation? What other math problems would you like us to cover? Let us know in the comments below!

Happy learning, and see you in the next video! 🎉

Thanks for Watching !!
@infyGyan ​

[afrv]

Good exercise; x= -1 is repeated in both equations; there are six solutions

[maxvangulik]

the left side can be factored: x^4(x^3+1)=x^3+1
dividing both sides by x^3+1 will need to avoid the x^3+1=0 case, which has a real solution of x=-1. As for the complex solutions, x^3=e^i(pi+2npi)
or cos(5pi/3)+isin(5pi/3) or -1
=1/2+isqrt(-3)/2 or -1
the x^4=1 case has 4 very easy solutions: 1, i, -i, and -1 again. There are 6 unique solutions.

[Idkwhattonamess]

Solved it in < 50 seconds

Edit: I should add that I only got four solutions within the < 50 seconds rather than 7