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0:04:30
The elastic portion of the stress–strain diagram for a steel alloy is shown in the figure - 3-26
0:06:01
The two pipes are made of the same material and are connected as shown - 4-40
0:08:12
The A-36 steel rod has a diameter of 50 mm and is lightly attached to the rigid supports - 4-79
0:05:48
The column is constructed from high-strength concrete and eight A992 steel reinforcing rods - 4-31
0:06:28
The assembly consists of three titanium (Ti-6A1-4V) rods and a rigid bar AC - 4-21
0:03:49
The 20-mm-wide block is firmly bonded to rigid plates at its top and bottom - F3-15
0:05:31
The assembly consists of an A-36 steel rod CB and an a 2014-T6 aluminum rod BA - 4-2
0:09:57
Draw the shear and moment diagrams for the beam - 7-51 (2)
0:04:18
The 100-mm-long rod has a diameter of 15 mm. If an axial tensile load of 10 kN is applied - F3-13
0:04:52
The two bars are made of a material that has the stress–strain diagram shown - 3-21
0:08:32
Atwood’s Machine. A 15.0 kg load of bricks hangs from one end of a rope - 5.15
0:10:19
The weight w is 60.0 N. What is the tension in the diagonal string? - 5.8
0:07:42
A large wrecking ball is held in place by two light steel cables - 5.6
0:04:59
It is observed that the time for the ball to strike the ground at B is 2.5 s - 12-85
0:04:45
When a rocket reaches an altitude of 40 m it begins to travel along the parabolic path - 12-73
0:04:37
Peg P is driven by the forked link OA along the path described by r = e^θ - F12-36
0:02:49
The car has a speed of 15 m/s. Determine the angular velocity at this instant - F12-33
0:02:53
The car travels up the hill with a speed of v = (0.2s) m/s - F12-32
0:05:37
When x = 3 m, the crate has a speed of 6 m/s which is increasing at 2 m/s^2 - F12-30
0:03:14
The boat is traveling along the circular path with a speed of v = (0.0625t^2) m/s - F12-27
0:04:51
A projectile is fired with an initial velocity of v = 150 m/s off the roof of the building - F12-26
0:06:19
Determine the speed at which the basketball at A must be thrown at the angle of 30° - F12-23
0:02:57
The box slides down the slope described by the equation y = (0.05x^2) m - F12-20
0:04:23
A particle is traveling along the parabolic path y = 0.25x^2 - F12-19
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