Integration Involving Inverse Trig Functions: Part 2

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This video explains how to apply the integrations rules involving inverse trigonometric function. Part 2 of 3

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Hello. Thank you for this video. Wanted to point out that at 3:58, when you divide by -18, the right side should read "x dx".

So "-1/18 du = x dx".

andrerouhani
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Sir, thanks for this video. Helped me alot

Hammadisteachingchemistry
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hi. thankss for this video. but i am thinking if you could factor out first 4 in your denominator so you will get 1-9/4x^2? to get a=1 and u=3/2x ?

giselleayson
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um at 2:38 how come when you solved for du/e^x the e^x wasnt factored out of the intergral. wouldnt it be e^x ∫du/u(√u^2-a^2)?

matthw