Given that \( \vec{A}+\vec{B}+\vec{C}=0 \) out of three vectors two are equal in magnitude and t...

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Given that \( \vec{A}+\vec{B}+\vec{C}=0 \) out of three vectors two are equal in magnitude and the magnitude of third vector is \( \sqrt{2} \) times that of either of the two having equal magnitude. Then the angles between vectors are given by
(a) \( 30^{\circ}, 60^{\circ}, 90^{\circ} \)
(b) \( 45^{\circ}, 45^{\circ}, 90^{\circ} \)
(c) \( 45^{\circ}, 60^{\circ}, 90^{\circ} \)
(d) \( 90^{\circ}, 135^{\circ}, 135^{\circ} \)
  1. PW Solutions
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