Coordinate Geometry : Equation of a perpendicular bisector : ExamSolutions

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A tutorial on coordinate geometry and the equation of a perpendicular bisector.

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you ARE the definition of a miracle sir, thank

matttower
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Thank you so much!
I have a test tomorrow and this REALLY helped

dylankriel
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I know it may not mean much.But this really helps the way you explain things make them so simple and understanding. Thank you so much! Appreciate it alot!!

zoerichard
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Absolute legend, this is so helpful thank you!

donjibz
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thank you for explaining it so simply. My maths teacher confused the hell out of me and didn't explain it step by step. (I'm doing A level maths)

vikiwikinana
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FP1 yes, FP2 hopefully next two terms

ExamSolutions_Maths
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loved it sir great way of teaching thank you

aizedhaider
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Seriously, you are the teacher of my teachers!

Nahiyan
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You explain it much better than my teacher :D

Strawberryturtle
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I have got a test tomorrow, your videos are playing a critical role sire

jaytripathi
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Do you also do Further Maths Vids? It would be sooo helpful!!! Thanks!

cybacyclonex
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what grade would this be on the 9-1 scale? Thanks

gfgrfgdfgfdgfd
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can you tell me how to work out co-oridantes when given an equation?

abbypollock
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Seems like a bit more work than necessary, especially since you end up undoing some of that work to get the required equation form. Using the point-normal form of equation of a line instead gets you to the solution more directly: subtracting the coordinates of B from A gets you the necessary normal, hence the coefficients of x and y, and after computing their midpoint you just need to subtract its dot product with that normal.

andydaniels
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Sir, what separates y and y1? I popped the numbers in y instead of y1 and x instead of x1 and i got a similar answer with all the numbers correct but my symbols flipped. I got 10x-12y+29 = 0 instead.

pokerockman
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Please can you upload another video on this please??

aqtzing
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Why did you do the reciprocal of the gradient... Is it because it is an improper fraction??

moeshafelix
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sir but wont the examiners subtract marks for using that equation instead of y=mx+c ???

zaibkhan
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Hi, I don't know what I'm doing wrong, but the gradient I got was -6 / -5 so I don't know where I am going wrong.

Has someone got an answer to this?

Thanks!

marziasahebzada