Show that (x - 2) is a factor of (x³ - 8)

(x - 2) is a factor of (x³ - 8)
x^3-8 factor of x-2
Using factor theorem, show that g(x) is a factor of p(x) , when p(x) = x^3 - 8 , g(x) = x - 2 .
one factor of x^3+8 is
#mathematics #polynomials