#26 || Problem#6 || show that [๐/๐๐’™ |๐’‡(๐’›)|]^๐Ÿ+[๐/๐๐’š |๐’‡(๐’›)|]^๐Ÿ=|๐’‡^โ€ฒ (๐’›)|^๐Ÿ || 18MAT41||

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18MAT41 : Module : 2 : If f(z) is regular function of z, show that
[๐/๐๐’™ |๐’‡(๐’›)|]^๐Ÿ+[๐/๐๐’š |๐’‡(๐’›)|]^๐Ÿ=|๐’‡^โ€ฒ (๐’›)|^๐Ÿ

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Sir one doubt diffrentiation of u^2 is 2u then y r u writting 2uux ?

sarafathima