Finding the equation of a curve from its gradient function | Tutorial 1 | ExamSolutions

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Here I show you how to find the equation of a curve using integration when given the gradient function dy/dx.

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Thank you so much for this, I was absent when my teacher was teaching this. You're a life saver. :)

chuckiieslover
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@LanRous It should be y=(1/3)(x^3)/3+c so when x=1, y=3 gives 3=1/9+c so c=26/9

ExamSolutions_Maths
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A curve is such that dy/dx=2x^2-5.if(3, 8) lies on the curve then the equation of the curve is ? Sir i select this one. 2/3x^3-5x+5 is this is answer sir

aurangzebkhan
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Just to sum it all up loving all your brilliant videos so far.... brings out every little detail needed to learn for exam or just understand de concept overall

bladervinay
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You explained much better than my maths lecturer XD

Thanks for the help :)

lukazio
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thank you for this video, really really helpful!

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@trexmanpop Thank you for your comment

ExamSolutions_Maths
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Thanks for the video, great explanation. One question though. What if I need to find the equation of a function given that the gradient is a vector, such as grad(fx) = [x1 + x2 + c1, x1 + x2 + c2]? Would integrating any of its components do?

jaime
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Great explanation, thankyou base god!

QuackSuperStar
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Hello, are the tutorials content for Pure Maths, Statistics and Mechanics updated for the new specification of Edexcel Maths AS Level (8MA0)? Thank you!

ozllrxs
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Hi sir! What would u do for trig curves

sunnysk
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Great videos :)

Thumbnail image for this video has the x and y coordinates reversed, which caused me some concern after I solved from the thumbnail and then skipped to the end of the video to see if i was right :)

WoakesEth
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If i have this case and i know that for x = 1 y =3
1\3(INTEGRAL OF (x^2)dx)
Then the result is (1/3)((x^3)\3 + c) or [(1/3)((x^3)\3) + c]?
I ask because c is different on each case.

LanRous
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Tamang nood lang ng Integral Calculus Videos. 💘 Para sa assignment, hehehe! 😁

kyaheric
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by any chance have you seen this sort of question in any of the AQA c2 paper?
thanks

purdevil
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Why do we have to integrate. Can't we just put x and y to find gradient?

asadsyedali
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do these videos still apply for the new course? thanks

osman