Dictionary comprehension with if else : Python tutorial 138

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Thanks for the free python course. I like your teaching style. you explain clearly. Really, you are a very good teacher.

mikku

# d={1:'odd', 2:'even'}
dic={}
for i in range(1, 5):
if i%2==0:
dic[i]='even'
else:
dic[i]='odd'
print(dic)
#DIC COMPREHENSION
didto={i:'even' if (i%2==0) else 'odd' for i in range(1, 5)}
print(didto)

arunavasamanta

You are a good teacher
Thanks for these

shubhamrai

can we write any condition in key ?
i wrote then it just print the last two numbers in same code that same condition in key and value just i

varuntanwani

How to use if elif else in dictionary, list comprehension

rachitmittal

Sir नमस्कार। सर मैंने अपने Android phone (itel mobile) पर एक ऐप इंस्टाॕल किया है "Qpython" but उसमें आपके द्वारा बताई गई यह स्टेटमेंट नहीं execute हो रही है---
sqs={f"Square of {num} is:" num**2 for num in range(1, 11)}
It is giving the err--
"Invalid syntax"
और यह एरर ज्यादातर is: की जगह point out कर रहा है। मैंने ऐप बदल कर फिर से कोशिश की लेकिन फिर वही एरर बार-बार occur हो रही है। कृपया मदद करें या कोई भी जानकार व्यक्ति। धन्यवाद।

hardcode

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