Can you solve this exponential problem

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Комментарии
Автор

Croyez-vous que quelqu'un qui se lance dans la résolution d'une telle équation, ait vraiment besoin qu'on lui rappelle les identités remarquables de base ?

antoinegrassi
Автор

Et si on commençait par remarquer que
4 + sqr(15) et 4 - sqr(15) SONT INVERSES l'un de l'autre ?
En effet (4 + sqr(15)) x (4 - sqr(15)) =
4^2 — 15 = 16 — 15 = 1
En posant Z = 4 + sqr(15) l'équation s'écrit tout de suite
Z^x + 1/Z^x = 62
on multipliant les deux membres par Z^x, l'équation devient:
Z^2x + 1 — 62.Z^x = 0 de la forme X^2 — 62X + 1 = 0
avec X = Z^x. Etc....
CONCLUSION : quand dans un TEST il y a BEAUCOUP de CALCULS alors on fait FAUSSE route. Pour trouver L'ASTUCE il faut d'abord la CHERCHER. 😉😉😉

antoinegrassi