Recursion One Shot - Advanced Level Questions | Placement (Tech)

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00:45 - permutation of a string
13:30 - CountPathMaze
24:39 - Tiling problem
35:17 - Friends pairing problem
42:18 - Subsets of a set

anantakhurana
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Here are time stamp, Like if it helps you.
00:45 - permutation of a string
13:30 - CountPathMaze
24:39- Tiling problem
35:17 - Friends pairing problem
42:18- Subsets of a set

imharry
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FINALLY DONE WITH THE RECURSION.ALTHOUGH I HAVEN'T UNDEERSTOOD IT WELL YET I AM MORE HAPPY TO FINISH THIS TOPIC.IT WAS FEELING LIKE A HUGE MOUNTAIN TO CLIMB.😎😎
THANKS APNA COLLEGE AND SHRADDHA DEE FOR THE CONTENT.

taxila
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Didi ki communication skills ab aman bhaiya ki jaisi ho gayi hai 😁😁😁😁🤪🤪😂😂😂😂😂👍👍

sureshm
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00:45 - permutation of a string
13:30 - CountPathMaze
24:39- Place Tiles of size 1xm in a floor size nxm
35:17 - Friends pairing problem
42:18- Subsets of a set

piklude
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I respect her way of teaching but recursion went totally beyond my head feel so suffocating to complete this... Without understanding

sumanshukla
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you are doing a great job; but it would be more helpful to understand if you can explain how the codes are running like in permutation of a string;

sujataoli
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Didi honestly, the C++ course is really amazing, the animations make it easier to understand too. But the only problem was the sir teaching. It wouldve been 200x better if you had taught the whole course.
This One Shot was so good that though I dont know much Java, I understood it very clearly.
Thank you so much.

nithinshukla
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Time stamp for this video]

00:45 - permutation of a string
13:30 - CountPathMaze
24:39- Tiling problem
35:17 - Friends pairing problem
42:18- Subsets of a set

sandeepkumar
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I m big fan of Sharda didi but recursion 3 classes went totally beyond my head plz if u see this cmnt make it more simple to understand

aniketkumarjena
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Your content is so good that it is difficult for me to wait for the 3 lecture of Recursion

digiflixindia
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These are really great tutorials!!! Thanks tonnes for creating content which is actually helpful, comprehensive and easy to follow along because usually what happens on interest is we keep navigating from one video to another because some or the other thing is not clear enough to proceed or somehow you run into issue and are blocked! But amazingly no such case here which is the best part of this channel!
Thanks again! Keep creating such quality content.

shaheenakhtar
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you can also use this base case in friend pair

if(n==1 || n==2 || n==0)
{
return n;
}

rajiv-
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Please DRY RUN bhi karke dikhao di. Ase first question hi samajh nahi aaya ki kaise konsa character print hua.

vishvjeet
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why cant i think such type of logic even after stressing my after it is done it feels like it was so easy!!!

bhavinsheth
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Thank you so much aman Bhayia itna sab humare liye karne ke liye 🙏🙏

vaibhavpuri
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aap ham logo ko apne barabar kahe intelligent samjh rahi hai

softcodying
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I am very big fan of you and your team mam...c++ placements course made me easy to understand apke liye kitni bhi tarif or wish karu kam hai..💝💝💝💓🖌️

rajeevranjan
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Please give timestamps also on the video since we know some of the problems and the approach to solve them. It will save everyone's time.

pixelsbyme
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Thankyou mam you are superb because how much you do for our success ❤❤❤

rishabhgaming.