The 18 Electron Rule for Transition Metal Complexes

Ok, so we understand how ligands bond to metals to form transition metal complexes, but how many ligands will fit? Well, remember the octet rule from general chemistry? There is a similar concept that we can apply here, which is called the 18 electron rule. 18 is bigger than 8 because transition metals have access to d orbitals. Let's see how this rule works now!

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[shepshep]

I just want to let you know you're a personal hero to me. Thanks for the lessons.

[vincentleong]

One of the best Chemistry tutors and it’s free

[nirnama.aksara]

This lesson is enlightening my insight

[turdferguson]

Question: why is the alkyne restricted to donating only 2 or 4 electrons? Why not 3 since it has a triple bond?

[Valdagast]

Does this become a 32-electron rule for the actinides and lantanides?

[Ensaima]

i should see your chemistry playlist. Becouse i dont understand 60% of your funny words

[JamesD]

How do you figure out the carbonyl groups are neutral?

[josipbroztito]

Pleasee make video about isolobal analogy

[eatshitlarrypage.]

5:53 I was trying to follow along and do the work myself, when I got the electron configuration of tungsten I got [Xe] 6s^2 4f^14 5d^4. At the given timestamp, you have it written as 6s^2 5d^4, leaving out the f shell. On Wikipedia, they have it listed as [Xe] 4f^14 5d^4 6s^2. I got my order by using the Aufbau principle and I'm assuming the order doesn't particularly matter, but why didn't you list the f block? Is it just assumed to be filled? Would it be valid to simply write [Xe] 5d^4?

[burgertblom]

If you count ionically, as you have done in the video, then for carbenes one needs to a priori know if it is Fischer or Schrock type to either treat it as a neutral 2 electron donor (the carbene), or a dianionic 4 electron donor in the case of a Schrock type system. Take (CO)5Cr=CR2 as a prototypical Fischer carbene: anionic counting (which in this example is identical to covalent counting) means that the count would be 5 x 2 (CO) + 6 (Cr) + 2 = 18 VE, but that is only because I know it is Fischer type, and hence the carbene is neutral 2 electron donor. If I treat it as Schrock type, then the CR2 fragment is 4 electrons 2- charge: 5 x 2 (CO) = 10 + Cr(2+) = 4 + 4 (CR2) = 18 VE (as in your table). But this is incorrect, since the Cr is in the zero oxidation state for Fischer systems... We get the same number, but the assignment of Cr(2+) in the ionic counting scheme is incorrect. So a better approach is covalent counting across the board, as one need not know a priori the charge assignment of a ligand. Same goes for carbyne counting (or alkylidyne).

[DILSHANYOOSUFCHEMISTRY]

Can you please explain how η5-C5H5 contributes 6 electrons to a complex ?

[troy]

It's such a shame I'am still studying but the anti is going to be fun hear and ever think at a pole N/S that there's the hole bend at that very centre between magnetic field lines the iron used as the bond or fabric hole mechanics!.😃😄😁😆😅 5 Smile's

[beastemeauxde]

Thank you for not shying away from the heights of your intelligence! Keep doing this type of science when you're not debunking pseudoscience!

[hinashahzadi]

Cp always contribute 5 e not 6 as you are telling??

[psyseraphim]

Hey Dave, love your content. Just dropping by to ask if maybe, just maybe, we could see a future collaboration between you and Forrest Valkai who does a lot of Tik Tok stuff and appears on Atheist Experience. It seems that neither of you do many (if any) collaborations but your style and inflection are so similar I feel like it might be a really great fit and could produce some epic, informative and entertaining content. Anyway keep doing what you're doing, much love.

[eldersprig]

so if an electron falls on the floor, if i get to it in 18...uh never mind

[harshsrivastava]

Why are there no comments lol (i was 2nd)

[mallelaxmikanth]

the interest to learn a new topic is completely dead after watching this video.

[Just-a-normal-guy-yt]

Sus