24 HOURS CHALLENGE 18#SOLVE #EQUATION #VARIABLE #SOLUTION #BEINGMATHEMATICIAN#QUARANTINEMATHTEACHER

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[sumitkundu]

Very conceptual sum and challenge, sir. The sum deals with the basic knowledge about linear and quadratic equations👏👍👍💪💪💪🥳🙂 🙂😃😃 😃

[sparshajit]

X is any rational no.
Example--1, -6, -4, -3, 2, 3, 4, 1.2, 2.2, etc

[siprasengupta]

Sir the answer will be = "X" is any natural number.

Swarnabha Sengupta Class :- 7 A DBB

[ashmitalahirimitra]

X is omitted and the equation equation with various results

[shrabanighosh]

Sir two answers can be:-
(i) x cannot be determined
(ii) x is any natural number

[swarnaliroy]

X is any natural number
Sreesweta Roy

[chandanbanik]

Sir, I think the answer is x=0
TAMOGHNA SAHA
Class-7A
DBB

[sandipseal]

Sir x is any real number
.... RISHITA SEAL

[aneekaandsanjida]

Sir,
After solving, it is cancelling out and at last becoming x=x . The ans cannot be zero otherwise it will be undefined. X/x should become 1 ..So I think the ans will be any real no.
This is amazing and a very tricky sum... Waiting for the solution


Aneeka Sharmila.Sjc class 8 A

[snehalpal]

X=-2 and X=3 i.e. the roots of the equation are(-2, 3)

[nabamitaghosh]

Sir, After solving the equation, everything will cancel out and it will be zero. So, this equation is usable in cases where we need to find the value of x. Therefore, x is any natural number.
-Susmit Ghosh of class 8, Don Bosco BANDEL.

[animesensei]

LHS
(X+2)(x-3)
=x^2-2x-6
RHS
x^2-x-6


Now let them get together for equation .
x+2x^2-6 = x^2-x-6
2x+x^2 = 0
It forms a quadratic equation where.
a=1
b=2
Find the Solution for:-
1x^2+2x+0=0

using the Quadratic Formula where
a = 1, b = 2, and c = 0

x={−b±√(b^2−4ac)}÷2a
x={-2±√(2^2-4 (1)(0)}÷2 (1)
x={-2±√(4-0)}÷2

The discriminant b2−4ac>0b2−4ac>0
so, there are two real roots.

Simplify the radicle:
x=(-2±2)÷2
So x has two values now.
Value 1
x=(0)÷2
x=0
And
Value 2
x=(-4)÷2
x=-2
So now x can be 0 and -2

[ankana_dia]

x is any whole number
Except -2 and 3 (because if x is -2 or 3, the left side will evaluate to 0)

[sumitkundu]

X can be expressed as a set ....
X = {x:x belongs to R or x belongs to C} . In other words this "equation" is not an equation. It can be called an identity, as it is applicable for any value of x. [ example of an identity is (a+b)^2 = a^2 + b^2 + 2ab ].

-- Sumit Kundu DBB 8.

[animeshdas]

Sir, x = any natural number except -2 and 0/0 is undefined...

[sparshajit]

X Is is 2 and -3
Proving:-
If x is 2, then
(X+2)(X -3)=(X^2)- X -6
Or. (2+2)(2-3)=(2^2)-2-6
Or. 4×-1= 4-2-6
Or. -4=2-6
Or. -4=-4

If x=-3 then
(X+2)(X-3)=(X^2)-X-6
Or (-3+2)(-3-3)=(-3^2)+3-6
Or. -1×-6=9+3-6
Or. 6=6

HENCE VERIFIED

-SPARSHAJIT

[sonalikoley]

X is any natural number.
----.... SAMPURNO KOLEY 7B DBB

[moupianath]

"X" is any real number..( positive and negative..too). as LHS = RHS....so if we put any value LHS comes to be equal with RHS....

[somnathghosh]

Sir X can be any Integer
Sourjya Ghosh Class 9 DBB

[smalltalks_]

Sir,
"X" is any natural number🙂