Set Theory Proof: Prove that if A union B is Empty then A is Empty of B is Empty

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Set Theory Proof: Prove that if A union B is Empty then A is Empty of B is Empty

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  1. The Math Sorcerer
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Комментарии
Автор

Is that for AUB=empty, then set A and set B must both be empty. Instead of A= empty or B=empty.

phkw
Автор

I think i got it,
If A=phi OR B= phi, then
It means
A= phi AND B not equal OR
A not equal phi AND B= OR
A= phi AND B=


In above 3rd statement is actually correct for A U B= phi but it is in OR with Statement 1 and 2 so statement 4 is valid for A U B= phi.

Iam i correct?

Marshall...-_-
Автор

but I wonder why A=phi or B=phi it be A=phi and B=phi.... isn't A union phi=A and
phi union understand proof is right but I feel some confusion....can you clarify it please?

mahmoudalbahar
Автор

Really nice vedio about set theory i started to understand it when i started watsh your vedio 👍

mahmoudmroweh