Leetcode 153: Find Minimum in Rotated Sorted Array - Java Solution with visualisation

*Finding Minimum Element in a Rotated Sorted Array*

In this video, we'll explore an efficient algorithm to find the minimum element in a rotated sorted array using binary search.

*How the Binary Search Approach Works:*

1. *Initialize Pointers:*
- `start`: Points to the first element of the array.
- `end`: Points to the last element of the array.

2. *Iterative Binary Search:*
- While `start` is less than `end`:
- Calculate the `mid` index.
- If the element at `mid` is greater than the element at `end`, the minimum element lies in the right half of the array.
- Otherwise, the minimum element lies in the left half (including `mid`).

3. *Return the Minimum Element:*
- After the loop, both `start` and `end` will point to the minimum element. Return `nums[end]`.

*Why Binary Search is Efficient:*

- *Time Complexity:* O(log n), where n is the number of elements in the array.
- *Space Complexity:* O(1), as we use constant extra space for the pointers.

*In this video, you'll learn:*

- The concept of a rotated sorted array.
- A step-by-step explanation of the binary search approach.
- A clear Java implementation of the solution.
- Analysis of the time and space complexity.

*Who should watch this video:*

- Java programmers looking to improve their algorithm skills.
- Anyone interested in data structures and algorithms.
- Those preparing for technical interviews.

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