Hamming Code - How To Find Corrupted Bit - Even Parity

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1100 1101 0110 is an EVEN parity 12 bit Hamming code that contains a single-bit error. What is the corresponding uncorrupted Hamming code?
  1. Scott Wickersham
  2. Hamming code
  3. computer science
  4. binary
  5. code
  6. math
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Комментарии
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awh. finally someone who speaks human language!

mohammad-karbalaee
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Thoroughly and easily explained! One of the few quality videos available on the topic on YouTube.

gabrieldylan
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This guy just saved me a couple hours of research!!

sp
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Clear, concise presentation and delivery. Everything I ever wanted from an educational video. Thank you :)

giladgur
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thatnk so much dude !! life saver the night before the exam

quantum_fiziks
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BRO YOU RE SO GOOD AT EXPLAINING THINGS <3

ZEEWX
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you are my superhero, been staring at my question for over 2 says wondering how they decided that the 7th bit is the corrupted one, thank you

faristhehonest
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I did not understand when my teacher explained but this video made so much sense!

lisa
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dude, u are unmatched istg, are u kidding me ?! in 4minuts i got it . i love you .

ojichan
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love u bro watched this last night very simple
🥰🥰

muhammadzaid
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New subscriber here! Very helpful video. Thanks and God Bless! 💛💕

perezroselyne-annb.
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have a test today and this video helped a lot....

lakshawilson
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Easy +Effective Explanation
You Rocked

Rohit-pfzk
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My lecturer made a real hash of explaining this. Thanks a lot for your video

jackhaugh
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2:33 why don't we marked the 4th bit as "?", If it is priority bits?

peace
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Thanks a lot mate one of the only video that make sense.

loremipsum
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i cane here to learn but your voice is so addictive

ejay
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Thank you...i appreciate yr effort for this

puonen.balakrishnan
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Well explanation, you made it much clear now, but shouldn't we write down P values with the data bits as well? you did so with P4 but doesn't the same principle hold for the rest of the P values too?

MoHaMmADAlmotaref
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I think that P4 position 4 should be a "?", but as long as it doesn't affect the result, I think it is ok. Thanks

gregorygrigoriadis