Is BaCO3 acidic, basic, or neutral (dissolved in water)?

To tell if BaCO3 (Barium carbonate) forms an acidic, basic (alkaline), or neutral solution we can use these three simple rules along with the neutralization reaction that formed BaCO3 .

First we need to figure out the acid and base that were neutralized to form Barium carbonate. The equation for BaCO3 is:

Ba(OH)2 + H2CO3 = BaCO3 + H2O
It is also useful to have memorized the common strong acids and bases to determine whether BaCO3 acts as an acid or base in water (or if it forms a neutral solution).

Strong acids: HCl, H2SO4, HNO3, HBr, HI, HClO4
Weak acids: HF, CH3COOH, H2CO3, H3PO4, HNO2, H2SO3
Strong Bases: LiOH, NaOH, KOH, Ca(OH)2, Sr(OH)2, Ba(OH)2
Weak Bases: NH3, NH4OH
Note that we are talking about whether BaCO3 is an acid, base, or neutral when dissolved in water.

- Salts of strong bases and strong acids: pH will remain neutral at 7.
- Salts of weak bases and strong acids: pH less than 7 (acidic).
- Salts from strong bases and weak acids: pH greater than 7 (alkaline).
Based on these rules, the solution of BaCO3 dissolved in water is Basic.

For polyprotic acids (e.g. H3PO4) it’s a bit more complicated and we need to use Ka and Kb to determine the pH of the resulting solution.

[dyar]

How did u know to choose h2co3 rather than hco3