Superposition Theorem with example

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The introduction of the principle of superposition in electric circuit and example with step by step solution.

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just a small, mistake, four years later and it is still you so much.

SkDaSoul

Thanks for picking this. I already heard that I did a mistake in the calculations, now I know where it is. I was a bit hurry to get it ready for my students before they set the test ;)

marinabelkina

The Final Answer i.e I = i1+i2 = (1.11+(-0.55)) = 0.56 Amp.

sinkarharshad

Despite the mistakes, thanks for putting in the effort to do this. Its very helpful, and i love your voice.

christopheredwards

@ 9:23 There is an error in the calculation of Req. Req = 10//4 + 5 = 110/14 = 55/7. By current division then i = -2 x (5/(5 + 55/7)) = -70/90. i2 = (-70/90)(10/(10+4)) = -5/9 Amps. By the way, i = -5/9 is the same value calculated by Mesh Analysis. Therefore, the total current in the 4 ohm resistor by Superposition is I = 10/9 - 5/9 = + 5/9 Amps. ∎

johnnolen

Theres a mistake, Mam . The equivalent resistance for Req = 10II4+5 = 7.857 Ohm :/

anasazmayeenzamee

Above all thank you for the formula..., and for showing us how it is done, ...Yr a blessing

tinotenda.

Thank You Marina For a Smooth and Easy Explanation Of Superposition!! I am Trying To Brush up on my Circuits Skills that I Learnt in Electronic Engineering Technology many many Years Ago!!!

reh

Your narration is superb. Thank you madam

great_India

Thank you for this video. You explained it so well, and that little mistake was easy to correct.

mayorhaggar

Thank you very much!! I watched a lot of videos but did not understand! After watching your video I have finally understood!

aruqyz

allahamdallah I`m alrealy Know where was da mistake .. anyway thank u 4 the videos it`s informative .. thanks a lot madam =)

mahamatissa

Hey really think you this is really helpful please don't give up carry on

ahmedmohammed

Ignore the mistake, the final answer is 1.11-0.56=0.55A ?

daniellai

Great video
Why did you stop making these

bebarshossny

its really helpful... i learned here... thanku

pallavichandimani

There was a mistake or i dont understand. 2.86+5 = ?

abdykaparkamilov

How did you find that current at 5:49? What's the name of the method that said you can take opposite resistance over sum of the two parallel resistors?

andreasmusic

what if there are dependent sources do we have to disconnect them too and then repeat the process for them too

tejasvagarwal

If I have two voltage sources in the circuit how can I solve it with super position?

abdelmonemhassan

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