Example of a flux integral, Multivariable Calculus

preview_player
Показать описание
Let's find the flux of F(x,y,z) = (x,z,0) across the paraboloid z=x^2+y^2 with outward-pointing orthogonal vectors. We go through how to set up this vector surface integral computation and then compute it. Error: at 8:10 I pulled -2 out front, but didn't change the sign of the second term (luckily that term has an integral of 0, so the final answer is correct).

If you are visiting my channel, please subscribe and check out the rest of my lectures on Multivariable Calculus!

#calculus #multivariablecalculus #mathematics #flux #iitjammathematics #calculus3 #surfaceintegral
Рекомендации по теме
Комментарии
Автор

Smart, does the problems, and explains the details, plus you don’t joke around but gets to the problem at hand. What more could you ask for. You should have a LOT more views. Even though you are extremely pretty, you do it with class and does not distract for the presentation.

rosskious
Автор

It appears that there was a sign error when factoring out the -2. The second (sin(v)) component should have a positive coefficient, but it ended up not mattering because the whole thing evaluated to zero in the end.

GLENNSCHEXNAYDER-nc
Автор

Thank you
You helped us
Thank you from the heart ❤️

ussamafadili
Автор

MANY MANY THANKS AND MANY MANY HEARTS AND ROSES TO YOU DR.BELVIN.SINCERELY YOURS
ADEEB.ADEEB.

adeeba
Автор

This is an excellent video. Thank you.

retiredaccount
Автор

Ha! I just wrapped up Units 6 and 7 of this series, with notes coming in at 107 pages. Now I must add.

eswyatt
Автор

Hi could you explain more the differences between upward/downward normal, inward/outward, and positive/negative orientation?

moondxstq
Автор

Hi, when I tried to do this question without parameterising the surface (I used dot product of F and the partial derivatives of z) I got -40π instead of 40π. Is it because I used upward pointing normal instead of downward pointing normal? Thank you so much

amandaliu
Автор

When I use Gauss' Divergence Theorem I obtain a different answer of 64pi, how come?

sportmaster
Автор

I think I’m misunderstanding something. It looks like there’s no intersection of the vector field and the paraboloid, so I don’t understand how it can affect the flux across the surface. The vector field is completely contained in the x, y plane, is it not? What am I missing?

glennschexnayder
welcome to shbcf.ru