Percentage of Shaded Region Algebra Math Question | JusticeTheTutor #maths #math #shorts

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You don't actually need to count the squares. Since the triangle's base is the same as the square's base and it's height the same as its height, it'd always be 1/2 of the square's area due to how the formulas of the shapes' area works.

lacintag
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Bro really restarted and forgot to edit out the first take

Just_Gent
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I don’t understand why math videos started being recommended to me, but I’m not upset about it. I’ve watched probably 30 or these videos, and I must say I’m quite entertained

vyyo
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You could also imagine cutting the square into a 5x6 left and a 1x6 right, where you realize that each triangle in there is half of the rectangle area each

niklasmkw
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You don't need to do any of that. Divide the total square into two pieces: the right column and the rest of it. Half of each piece is shaded, so half of the total is shaded

seankauder
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The height of triangle (line segment) divides the 6x6 square into two rectangles (5x6, 1x6). It can be clearly seen that the triangle is taking up half of each rectangles. So the ans is 50%.

radhakrishnamohanty
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It is a triangle.
1/2 * base * height
a square has formula
base * height.

Given that base and height are the same in both cases. the answer is 50%

j.p.vanbolhuis
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Is solved by inspection. No math needed.

marvs
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yep! alternatively, you can split the square into two parts, the left 6x5 and the right 6x1, and see that each section is cut exactly in half. that means in total half of the square is shaded. This helps if you don't the know the size of the square, or the formula for the area of a triangle.

ayn
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You don't need any calculation. By observation you could conclude 50%. You have two rectangles that both have 50% of their blocks shaded.

thetravellersboots
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there are two easier way to do that,
1) triangle surface is calculated by "height x wide * 0.5" since the height and wide is the same as the square, the sureface area is 50% of the square
2) you can see it as 2 rectangles, a 5x6 and a 1x6, you see they are both being cut by half by a triangle, so the big triangle is half the size of the big square

johnzt
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In 9th class, there was a chapter named as Areas of Parallelograms and Triangles.
In that there was theorem that
if a triangle and a parallelogram share a base and are between the same parallels, then the area of the triangle is half the area of the parallelogram. Since square is also a parallelogram. Therefore. You could've just used that theorem and you didn't even needed to find the sides of squares!

YashChavan-myqg
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Quicker way for the problem is….. you can clearly see the shaded area is exactly a diagonal line across each section of the square. So it is 50%.

kurienthomas
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This doesn't require calculations. Just a simple visualisation technique is needed

CidKagenouNotShadow
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Solving a problem intuitively (without arithmetic) should always be the first step.
It helps to fully understand the problem and (in this case) can sometimes give you the answer very quickly.

rediculousman
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I solved it visually. There are two 50% shaded rectangles, first one is 5x6 on the left, you can see how it splits in halves with the shaded triangle, the second one on the right 1x6 vertical, also splits to two triangles. so total shade is 50%.

honestcommenter
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if you just look at it the triangle is taking up half of the first 5x5 on the left and also half of the 1x5 on the right so it’s just half

charlize
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The area of a rectangle a*b
The area of a triangle (a*b)/2
Then, the area of any triangle is half that of a rectangle of similar height and length.

betosasieta
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Highly unimaginative: Moving the upper corner of the triangle does not change the area, thus moving it to the right gives you ‚half‘ using one look

willemjansen
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You should clarify the area is the formula for right angle triangles only, which is why you split it.

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