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Integral of ∫dx/sqrt(1-x^2) by Trigonometric Substitution
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In this video, we work through the steps to find the indefinite integral or anti-derivative of:
∫dx/sqrt(1-x^2)
with the term 1 - x^2, it is indicative of a trigonometric substitution, so we try:
x = sin(theta) with dx = cos(theta)
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Please ask me a maths question by commenting below and I will try to help you in future videos.
∫dx/sqrt(1-x^2)
with the term 1 - x^2, it is indicative of a trigonometric substitution, so we try:
x = sin(theta) with dx = cos(theta)
Thanks for watching. Please give me a "thumbs up" if you have found this video helpful.
Please ask me a maths question by commenting below and I will try to help you in future videos.
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