Does this series converge?

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Theres a another way to solve the [n/(n+1)]^n limit, which imo is slightly quicker.

[n/(n+1)]^n
= [(n+1)/n]^(-n)
= [1+1/n]^(-n)
= [(1+1/n)^n]^-1
As n-> inf, (1+1/n)^n approaches e (one of the definitions of e), so the answer to the limit is just e^-1

Ninja
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I could immediately tell if it converges and limit of the ratio with Stirling approximation.

КириллЙошкин
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That logarithm-ing and L'Hopital is completely unnecessary... It's obviously the reciprocal of the limit definition of e (Euler's).

reevegarrett
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I'm so glad I never needed to use this after college

coolbrotherf