Prove that 3.5^2n+1 + 2^3n+1 is divisible by 17

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Mathematical Induction
  1. Abhilash 2021
  2. Inter maths
  3. Intermediate maths
  4. Inter mathematics
  5. Intermediate mathematics
  6. Mathematical induction
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Prove that 3.5^2n+1 0:11:07

Prove that 3.5^2n+1 + 2^3n+1 is divisible by 17

For each `n 0:01:29

For each `n in N, 3.(5^(2n+1))+2^(3n+1)` is divisible by

MATHEMATICAL INDUCTION. 1+3+5+7+....+(2n-1)=n^2 0:05:37

MATHEMATICAL INDUCTION. 1+3+5+7+....+(2n-1)=n^2

3.5^2n+1 + 2^3n+1 0:09:18

3.5^2n+1 + 2^3n+1 is divisible by 17 | Mathematical Induction @EAG

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Mathematical Induction Proof: 5^(2n + 1) + 2^(2n + 1) is Divisible by 7

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#8 MATHEMATICAL INDUCTION Prove that 3[5^(2n + 1)] + 2^(3n + 1) is divisible by 17

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Prove 3^(2n+1) + 0:05:07

Prove 3^(2n+1) + 2^(n-1) is divisible by 7 using Mathematical Induction

PROVE THAT 1+3+5+...+(2N-1)=N^2 0:10:27

PROVE THAT 1+3+5+...+(2N-1)=N^2 USING MATHEMATICAL INDUCTION.

Induction: Divisibility Proof 0:09:54

Induction: Divisibility Proof example 1 (n³ + 3n² + 2n is divisible by 6)

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INDUÇÃO FINITA: 1+3+5+7+...+2n-1=n² 0:12:17

INDUÇÃO FINITA: 1+3+5+7+...+2n-1=n²

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Sequence sums by Archimedean property: lim(n→∞)⁡(3n+1)/(2n+5)=3/2 and lim(n→∞)⁡(n2-1)/(n3+3)=1/2...

Prove that: `((2n)!)/(n 0:03:38

Prove that: `((2n)!)/(n !)={1. 3. 5 (2n-1)}2^ndot`

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2.ii) 1+ 3 0:06:31

2.ii) 1+ 3 + 5 +....+(2n–1) = n² Using principle of mathematical induction show statements for all n...

If u(n)=(2n+1)/(3n+5) show 0:10:40

If u(n)=(2n+1)/(3n+5) show that lim un = 2/3 by definition of limit.

Mathematical Induction with 0:08:08

Mathematical Induction with Divisibility: 3^(2n + 1) + 2^(n + 2) is Divisible by 7

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Prove by the principle of Mathematical induction |3^2n -1 is divisible by 8 | Mathematical Induction

2.v) 1²+3²+5²+....+(2n–1)²=n(2n–1)(2n+1)/3 Using 0:09:20

2.v) 1²+3²+5²+....+(2n–1)²=n(2n–1)(2n+1)/3 Using principle of mathematical induction show for all n....

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Using principle of 0:03:18

Using principle of mathematical induction, prove the following `1+3+5+...+(2n - 1)=n^2`

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7. Proof of 1^2+3^2+5^2+...+(2n-1)^2=n(2n-1)(2n+1)/3.