Introduction to Thevenin Equivalent Circuits

In this lecture, we introduce the Thevenin equivalent-circuit theorem, and show how to replace circuit segments with their Thevenin equivalent, and then use the Thevenin equivalent to solve for unknown voltages or currents in a circuit.

[jeremykinnear]

I wish my prof gave as much effort in teaching this. The little things you explain (like how you determined Voc in the first example) are what make the biggest difference, and my guy seems to just think its intuitive for us. Thanks!

[tianxiaowang]

Thank you Timothy! I think this is a very useful video offering simple but typical example of solving a Thevenin Equivalent circuits. However, it would be a bit difficult for people without any idea of what Thevenin Equivalent circuits means to understand the workings, and many are confused by the "intro".

[ECEMadeEasyBySchulz]

The 8A current flows downward through the 2 Ohm resistor; therefore, the voltage will drop from top to bottom. In other words, the 16V drop across the resistor and the 12V drop across the voltage source are in the same direction.

[Anikung]

This is a really great intro video to the concept. Its helped me a lot more than my professor. Thanks!

[KasHr]

Nevermind I got it 11.6v is across 4ohms resistor so I got to do 11.6v-5v to find voltage across 6ohms. Very helpful video thanks.

[dbsz]

For people confused about the last example "ignoring" the 2 ohm resistance: Just follow the earlier example where you set all sources to 0. This means the 4 amps current source becomes an open hole in the circuit, no current will flow through the 2 ohm resistance, only the 4 ohm one. Therefore you have Rth = 4 ohms. You know the Ioc = 4, Vth = Ioc * Rth = 4 * 4 = 16

[TurtleboyTom]

Thank you so much! This is the clearest lesson I've seen on this stuff. And the music put me in a good mindset :). If I pass this class, I owe it to you. Keep making videos, please!

[ishaagarwal]

in the last example, the there will be 4A current flowing through the 2ohm resistor so 8V drop...could u please explain why it was not considered?

[wavejumpinseadoo]

Great video! Really helped me out before my midterm since I got sick and couldn't study. You're also really good at writing on the computer! Keep up the great work.

[jn_gutierrez]

Thank you so much. Much better than my [PhD] teacher!

[TheSysifos]

I was thinking about becoming a Electrical engineer. But after i started doind Thevenin equivalents, i am seriously rethinking my whole life.. i hate it

[chrisgalluzzo]

1st of all the music is very pleasant and I appreciate it in this time of frantic material review

[salmoonfaiaz]

Thank you very much, it was an easy and clear explanation.

[markbouwman]

at 3:43, isn't it subtracting the 12 volts due to the polarity direction of the volatge source?

[beckyherr]

Thanks so much for your videos! After watching them I was able to get an A on my quiz :D

[ECEMadeEasyBySchulz]

Depending on the other sources in a circuit, current can flow in either direction through a voltage source. In this case, the current source determines the direction of the current when we are analyzing the open-circuit voltage.

[KasHr]

For the last example, I did it using node voltage analysis for node at top middle.
-4 + (v/4) + ((v-5)/6) =0 I got voltage of 11.6v. You got 6.6

[Kevin]

Timothy Schulz is a boss at circuit analysis!

[mohammedalameri]

Thank for the great video. I really got a good deal of information from you. 

[saadamiens]

Thank you so much please keep doing tutorials on electronics