Mechanical Engineering Thermodynamics - Lec 9, pt 1 of 5: Reversible Steady-Flow Work

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  1. Ron Hugo
  2. Mechanical Engineering (Professional Field)
  3. Thermodynamics (Field Of Study)
  4. UCalgary
  5. Schulich Engineering
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Комментарии
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Sir, why vdp work has negative sign for expansion process and and positive vdp for compression process? Plz clear my doubt.

shivanshpandey
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In a steady flow system wouldin Ein = Eout bc dE/dt= 0

asanajohnson
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Thanks for the video professor. You derived the Gibbs equation for a closed system but here it was applied to an open system. How is this reconciled?

nikannow
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@Ron Hugo. Assuming a compressor runs from startup. Molecules first compress before air displacement takes place. So if we consider the partial diffential of flow work. dPv = Pdv + vdP. How would you determine the flow work if fluid would be compressible. Change in P and v. This puzzles me about the gibbs equation because the flow energy in a closed piston chlinder device for isothermal process using vdP yields the same result and Pdv. And yet we use Pdv as internally reversible for closed systems.

MrZealot