Circles Class 10 Maths Important Questions & Problems | CBSE Class 10 Board Exam Preparations

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In this episode of Class 10 Term-2 Crash Course Series, we take up CBSE Class 10 Maths Chapter 10 - Circles. Circles Important Questions along with Solutions will be discussed in this BYJU'S LIVE Crash Course session, which helps you to know the CBSE Important questions and get prepared for Class 10 Term-2 Board Exams.

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00:00 Circles Class 10 Maths Important Questions
2:19 1st Question
6:21 2nd Question
11:30 3rd Question
18:19 4th Question
24:53 5th Question
34:08 6th Question
43:03 Homework Question
44:28 Upcoming Session

#ByjusClass10 #CbseClass10 #Class10Maths #Circles #CirclesClass10 #CBSETerm2 #Term2Preparations #Term2CrashCourse #Term2Maths #Class10Term2 #Byjus #Liveclasses #Onlineclasses #NCERTbooks

[BYJUSClass]

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[yasharthkesarwani]

Homework Answer:-
Solution1. We know that the lengths of tangent drawn from an exterior point to a circle are equal.
Then, TP =TQ
Given that angle QTP = 100°
angle OQT = angle TPO (each equal to 90°) because the tangent at any point of a circle is perpendicular to the radius through the point of contact.
So, In quadrilateral, POQT
angle POQ + angle OQT + angle QTP + angle TPO = 360°
angle POQ + 90°+ 100° + 90°=360°
angle POQ =360°-280°
angle POQ = 80°
Hence, the value of angle POQ = 80°.

[rithizx]

Question:
Gn:Angle QTP= 100°&
Angle OQT = Angle OPT = 90° ( since tangent is perpendicular to radius through point of contact)
By using angle sum property of quadrilateral angle POQ+ angle OQT + angle OPT + angle QTP = 360°
=> Angle POQ + 90+90+100= 360
=> Angle POQ = 360-(90+90+100)
=> Angle POQ= 360-280
Therefore, Angle POQ = 80° :)❤

[charvi]

Homework:
In quadrilateral OPTQ,
∠OPT + ∠PTQ + ∠TQO + ∠POQ = 360° [Angle Sum Property of a Quadrilateral]
i.e., 90° + 100° + 90° + ∠POQ = 360°
So, ∠POQ = 80°
Therefore, the value of ∠POQ is 80°.

Thank you ma'am for the amazing explanation. You always clear the doubts of each and every student.🥰🥰🥰

[fenilsata]

Answer of Homework Question = 80°

Explanation :
TQ and TP are the tangents to the circle from an external point .

Now if we observed then we get the idea that TQOP forms a cyclic quadrilateral it that ..

By Angle sum property of cyclic quadrilateral
Angles ( OQT + POQ + OPT + QTP ) = 360°
90°+ X + 90° + 100°= 360° (Tangent TQ and TP are perpendicular to the radius of circles therefore it is 90°)

180° + 100° + x = 360°
X = 360° - 280°
X = 80°

Angle POQ = 80°

OR
Now if we observed then we get the idea that TQOP forms a cyclic quadrilateral it that ..

Therefore, opposite angles forms 180° ....
Angle QTP + Angle POQ = 180°
100° + Angle POQ = 180°
Angle POQ = 180°-100° = 80°

[bhagyavardhan]

Answer to Homework Question
*1st way*
Angle OQT = 90
Angle OPT = 90. ( Radius is perpendicular to tangent)
Angle PTQ = 100
In quadrilateral TQOP
Angle OQT + Angle OPT + Angle PTQ + Angle POQ = 360
Angle POQ = 360 - 280
Answer is 80°

[DDipak-oyju]

Good evening mam my name is Dipak
Homework Answers:-
Angle QTP + Angle POQ = 180°
100° + POQ = 180°
Therefore Angle POQ = 80°

[krvinod]

Tangents are equal
(TQ =TP)
OQ=OP ( Radii)
TQO=TPO =90°
QTP+TPO+TQO+QOP=360°
100°+90°+90°+ QOP = 360°
280°+QOP=360°
QOP = 360°-280°= 80°👍👍

[rishupandey]

HOMEWORK QUESTION:-

Angle T +Angle O= 180°
So, Angle O=180°-100°
=80°

[nikhmi]

Answer oc homework question is
Angle OQT =90° and QPT=90° due to the theorem and angle QTP =100(Given)
By adding 90+90+100+QOP=360°
So 360-280=80°
And answer is 80°

[nikeshmadavi]

Homework Answers:-
Angle QTP + Angle POQ = 180
100 + POQ = 180
So Angle POQ = 80 degrees..

[ananyaap]

Ma'am can u cover statistics next week

[aiswarya]

HW ANS : 80
ANGLE OQT AND ANGLE OPT =90+90= 180 ( TANGENT PERPENDICULAR TO THE RADIUS).
AND GIVEN ANGLE QTP = 100
THEN, ANGLE POQ = 360°-(180° +100°]
= 80°..
And Thanks byjus❤

[sethupalaniappanixa]

Angle POQ + Angle OPT + Angle OTP + Angle TPO = 360° ( Angle sum property if a quadrilateral ).
90° + 90°+ 100° + Angle POQ = 360° ( OQ is perpendicular to TQ and OP is perpendicular to TP ).
Angle POQ = 360° – 280° = 80°

[mythicalyt]

Homework:
In quadrilateral OPTQ,
∠OPT + ∠PTQ + ∠TQO + ∠POQ = 360° [Angle Sum Property of a Quadrilateral]
i.e., 90° + 100° + 90° + ∠POQ = 360°
So, ∠POQ = 80°
Therefore, the value of ∠POQ is 80°. ive submitted ma'am

[induprabha]

43:08 homework answer: angle poq=80 degree

[gayathri]

Ans: 80°
In cyclic Quadrilateral opposite angles sum up to 180°

[prasadvanka]

The angle inclined by tangents and angle subtended by radii are supplementary so angle PTQ + angle POQ =180° . So angle POQ = 80°

[dimplethresiabenny]

Somebody pls explain question 3 why can't we take r as 90 since radius perpendicular to tangent?

[pransu]

Awesome session ma'am
Watching for boards 23 🔥😁❤️🙌