SSLC MATHS ONAM EXAM | MOST IMPORTANT QUESTIONS | EXAM WINNER SSLC | SSLC EXAM

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Welcome to Exam Winner, your ultimate destination for SSLC Maths tutorials! In this video, we dive into Chapter 2, focusing on the intriguing topic of Circles, also known as വൃത്തങ്ങൾ in Malayalam.

Our expert instructors provide a comprehensive tutorial on Circles, covering essential concepts in SSLC Maths. Exam Winner is dedicated to helping you understand and master these important topics.

Join us as we explore the fascinating world of geometry, delving into circle theorems, arcs and chords, tangents and secants, central and inscribed angles, properties of circles, circle equations, and geometric constructions. Discover the fundamental principles that govern circles and their relationships with other geometric elements.

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ExamWinnerSSLC
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Exam winner ഞാൻ ഇതു വരെ കണ്ടിട്ടില്ല, maths എനിക്ക് ഒട്ടും അറിയില്ല😞പക്ഷെ ഈ ക്ലാസ്സ്‌ കണ്ടപ്പോൾ Happy, Thank you sir🥰

Hamna
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<P=30° (180-70+80)
<PBD=80° (supplymentary)
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rajeenaali
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a) <p=30°
b)<pbd=80°

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malavikagireesh
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a) <P = 180°- (70° + 80°)
= 30°
<C = 80° (given)
:. < ABD=100° ( Supplementary angle )
:. <PBD = 80° ( Linear Pair )

donadanis
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<A = 70, <PDB = 70 ( exterior angle of a cyclic quadrilateral =interior angle at opposite vertex)
<C=80, <PBD=80( exterior angle of a cyclic quadrilateral = interior angle at opposite vertex)
<P = 180-(80+70) = 30

susmithas-sikf
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I have started to watch exam winner class after 9th standard Onam exam.Till I am watching the classes. Now I am in 10th standard. The classes are too amazing and helps to improve more more concepts.Thank you Exam winner for this Great Classes
<P=30°
<PBD=80°

reshmishyjith
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< P = 30 degree
< pbd = 80
thanku exam winner for this valuable class

jithujayakumar
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Angle P =30 degree
Angle PBD = 80 degree
Thank you allen sir 🥰 polii class aayirunu ellam sett...🔥🔥🔥🔥❤

Niru..
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(P=30°)
(PBD=80°)
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Ebilff
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Angle A and B, C and B are supplementary angles so angles in the quadrilateralABCD B=100 D=110 angle PBD=180-100=80.angle //

sreekumark
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< P= 30°
< PBD = 80°
Thanks for this beautiful class




❤A BIG FAN OF ALLEN SIR & ALEX SIR❤

reejap
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Angle PBD =180-80=100°
Angle P =180-(80+70)
=180-150
=30°

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adhilameen
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P = 30°
PBD = 80°
THANK YOU ALLEN SIR, VERY USEFUL CLASS
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afisinuau
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Ans:- Angle P = 30°
Angle PBD = 80°
Thankyouh allensir for this wonderful classss❤️‍🔥🎉

fasnasavad
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<p=30°
<PBD=80°
Thankyou exam winner❤❤

fida
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Angle A=70°
Angle C=80°

Measure of Angle P=30°
180-(80+70)=180-150

Angle PBD=80°


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merinshibu
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<p=180-(70+80)
=180-150
=30°

<PBD=80°
=ABCD is a cyclic quardilator.
=<ABD=180-80
=100°
<PBD=180-100
=80°
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AbdullaAbdulla-cwzu
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IF Angle A = 70° And Angle C = 80°
Then angle PBD = Angle C =80°
Similarly
Angle PDB =70°
So Angle P = 180-(70+80)=30
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Ramzanworld
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Angle P=30
Angle PBD=80
thank u allen sir for this amazing class thanks to the efforts that is taken by all the teachers at exam winner i watch live classes regularly maths was hard for me especially circles but after watching allen sir classes i am shocked that i m improved in maths and also thanks to alex sir because of the physics class and i am proud to be a part of the exam winner family..❤❤
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sunilvarghese