How To Prove Bernoulli's Inequality

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Third method:

The two sides if the inequality are equal at x=0. The derivative of the RHS is n, and the derivative of the LHS is n(1+x)^(n-1) >= n, since 1+x > 1. So the LHS is increasing at a faster rate than the RHS, so the LHS must always be at least as large as the RHS

seanfraser
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You could have taken n=0 as your base case

neuralwarp
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How do you use this to prove a sequence is growing sequence

EpsilonDelta-ky
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Why set x > 0 here rather than > -1 like the principal seems to originally state? is it just a simpler approach and the full proof would have a separate case for between -1 and 0?

sammyasher
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Nice." I hope you enjoyed it... don't forget to comment, like..." and you syber don't forget the please let me know after the i hope you enjoyed it!😃💯

yoav
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Thanks 🙏
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