Special Case of Routh Array Case II

Special Case of Routh Array Case II
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Lecture By: Mrs. Gowthami Swarna, Tutorials Point India Private Limited

[TutorialsPoint_]

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[dhananjayreddy]

1)..1/z⁴ + 1/z³ +2(1/Z²) +2(1/Z)+5=0
2)..1/Z⁴ +1/Z³ +2/Z² + 2/Z +5/1=0
3)..take common denominator z⁴
4)..(1+z+2z²+2z³+5z⁴)/z⁴=0
5)..5z⁴+2z³+2z²+1=0

[wanderlust]

Multiply the entire equation with z^4 and then rearrange from highest power. For example z^4x5=5z^4 will come first and the last one will be z^4x(1/z^4)=1 which is placed at the end

[govinda]

Dear One, your teaching style is very good. Your video helped me a lot. I thank you very much

[vimladevi]

1.put 1/z in place of s in the given equation.
2.now multiply the new equation formed by z power 4.
3.rearrange it.
(1st column of each row should be non- zero, if any one of the rows has zero in the 1st column then only this method works)

[himanshutanwar]

Now I feel that I am able to clear my sessional exam easily . I saw first teacher teaching in the way which is easier to understand.
Thanks a lot mam

[blessingshenjere]

I have used your videos for 1 year now, the explanations are easy to follow 🙏. Be blessed ma’am

[mandavasairaghavendradines]

Name of the video should be "Special Case of Routh Array Case I"

[jyotiramoshi]

All of control system vedios are very nice mam....and they are very helpful to us...😘

[malomboaninga]

I'm writing a test on Tuesday on Stability System "Routh Hurwitz Criterion" I'm sure after watching these videos, I'm going to score 100%. many thanks ma'am.

[bijjamprasanna]

The way of you explaining is very clear mam....it's very easy to understand

[sumittiwari]

Thanks to Tutorials India😊 and big thankyou to mam 😊🙏
I easily understood mam I was so much confused .
Thank u so much ❣️

[sreekarana]

Excellent teaching..very easy to understand..thanks a lot mam

[imtiyazalam_IIItian]

Thank You So much madam for this amazing Playlist of Control System

[k.amaresh]

Thank you very much. These videos are very much helpful and wonderful explanation mam. Please continue to help us. I'm doing feedback control systems subject in Italy and this video is helping me a lot!

[subarnasubedi]

If you could not grasp the idea of cross multiplying with 1/z here's what you can do simply take the LCM of ie 1/z^4 in this case and chage the partial fraction into a single fraction term .

[ArshadIqbalBEE]

by seeing comments here, I realized why engineers don't get job easily

[arunsharma]

Nice classes maam
But u should not skip those multiplication steps
It was really confusing

[SaiKumar-xgti]

5:03 cross Multiple I'm Not understood plz tell the Formula..

[kunaldave]

5:14 if we multiply with 5 then ans will be 10z2.
Plz correct me.