Aptitude Made Easy Problems on Calendar full series, Learn maths #StayHome

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The method of substracting 1 from leap year dates is giving irregular answers.
It works on 29th February 2012 as shown in the video, I tried to check if it worked on 28th February 2012 and rest assured it was working.
But on trying the method on other leap years dates:
- 06 April 1896 - Remainder was 1 i.e. monday
- 05 October 2016 - Remainder was 3 i.e. wednesday
- 14 August 2004 - Remainder was 6 i.e. saturday
Upon checking the correct days for the mentioned dates, the answers were all correct without the need to apply the (-1) rule. Why the discrepancy?

Edit: I've figured out the pattern. Essentially, all dates in a leap year before the leap date are subject to the (-1) rule but not the ones that come after it. In simple terms in a leap year, we need to apply the rule on January & February but needn't apply the same on the rest of the year.

chatur_boy
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I usually don't comment, but u explained it very good, now I can solve all aptitude question regarding years and dates
Thank you

Busyguy
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1.) I simply pre-memorized all 366 possible dates as a value from -3 to 3.
2.) Then I just add that to one of the 4 possible century codes of 2, 0, -2, or 3 (7 possible century codes for Julian from -3 to 3) and finally,
3.) Add that to a pre-memorized value for each of the 100 years from 00 to 99.
For example, my birthdate of March 19, 1982 goes:
-2+3-3=-2 so Friday! Or shortcutting, I just cancel the 3 and -3, and -2 is Friday! The fastest way to do this is to pre-memorize all 100 year values from 00 to 99. Then I just add that to the century code and finally add that to a pre-memorized value for each of the possible 366 dates (these 3 values can be added together in any order you like). For example, June 15, 2012 would simply be:
2+2+1=5, so Friday!
June 15 always has a value of 2 (pre-memorized)
2000's has a century code of 2
and,
year 12 always has a value of 1 (pre-memorized)
2+2+1=5, Friday!
Anytime leapyear happens just subtract one from the answer for January or February only, all other months stay the same!
I calculate any day of the week using my method in less than a second, almost instantly to 2 seconds tops if I'm thinking a bit. I do both the Julian and Gregorian calendars in both AD and BC infinitely into the past or the future.I do other cool tricks that aren't heard of very often, for example since this calendar math can be viewed as just a simple addition problem, we can also solve for a missing value using subtraction! For example, if we already know the day of the week to be Friday for example, we can solve for a possible month/months or even a date from 1 to 31 or even a possible year or century.
Example: Which month or months did Friday the 13th fall on in 1899?
1899 was a Tuesday year (-2+4=2) or (5-3=2). So, Tuesday was the 10th since 3 days later was Friday the 13th.
So, 2+13+x=5 (Friday)
x=4 because 15+(-10)=5
-10+14=4
Mod7 arithmetic
Only January and October had a month code of 4 😁. So it only happened twice that year, in January and in October. Also we can say more intuitively that since 1899 was a Tuesday year, and Friday being 3 days later, which month/months had the Doomsday of 3, 10, 17, 24, 31? and obviously that is only January and October.
If the question changed to what were all of the Fridays in January and October for example in 1899?
We can say "the 6th, 13th, 20th, and 27th"
If someone were to instead ask for example on Friday the 13th from 1883 to 1900 what year/years did that happen?
We can say "only in 1893 and 1899"
In this situation we just needed to find the missing year code of (4 or -3) and only 93 and 99 have that year code in that date range. Likewise, we could have instead solved for the century 😉 also if already given a year.

thecalendarninja
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I Answered 3 answers out of 3 questions in recruitment test after watching this video. Thank you to the freshersworld team!

asifalikhan
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I got it.
But our respected Madam forgot to mention one important point, which might be the cause of some mistakes popping up when solving the case of March, 12, 2016.
"In case of leap years, only subtract 1 from the last remainder for January and February. For the rest of the month, ie, March to December, the last remainder determines the day of the month"

Thank you.

jacob.kipgen
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Guys she missed to tell something imp, in a leap year if it's before 29 th Feb minus 1 the remainder and if it's after 29 Feb don't minus because the minus 1 & the extra day 29 Feb gets cancelled so you don't need to minus 1 after 29 Feb in a leap year and for 29th Feb day minus 1 for reminder 👍🏻

charan_editz_
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The way u have explained was really elucidate. Each concept is nicely quoted so that viewer could easily understood 😊😊

pragatirathore
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If she's my teacher i ain't bunkin a single class😜😜

sriharsh
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Madam iam in a Telugumedium student but chala Baga understand avutundi thank u soo much

vijaykumarkorru
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For the 2016 example shouldn't we consider that is it a leap year and subtract 1 from the remainder at the last step to determine the day? 2004, 2008, 2012, 2016, 2020, 2024 ect can be divided by 4 so we can tell that they are leap years.

pampospanagi
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So Helpful Thank You so much. I am in 5th and in this quarantine days i wanted to learn something new so i took the chapter, Calendar. It is also in our syllabus. THX. I am so prepared.

amaderspams
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Your videos are "nothing but" amazing. 😉👍

AnshGupta
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Yesterday u disappointed me not uploading a full length aptitude vedio....plz one humble request plz create a separate a vedios on playlist and it will be useful

shaklinmusthaq
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We have to subtract one form only first two months (jan&feb) while calculating a day of leap year.

p.surendra
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Mam a small doubt. In the first part of the video, the second sum (with 5th october 2016) is a leap year. But why mam we didn't subtract 1?

chitraduraisamyk.p
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Thank you. I'd finished my C program with this algorithm.

virtualwork
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I am surprised 😮 with your flow of English.

shalindersinghrana
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Super explaination and Osm teaching Levels madam 😊

venuraja
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What a great day, I learned so many from your class Thank you sister.

rajeshvms
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Beauty with brains! Thank you for the video...Very Helpful!

hailrishi